제출 #1047539

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
1047539		c2zi6	Text editor (CEOI24_editor)	C++14	16 / 100	525 ms	268936 KiB

Main

#define _USE_MATH_DEFINES
#include <bits/stdc++.h>
#define ff first
#define ss second
#define pb push_back
#define all(a) (a).begin(), (a).end()
#define replr(i, a, b) for (int i = int(a); i <= int(b); ++i)
#define reprl(i, a, b) for (int i = int(a); i >= int(b); --i)
#define rep(i, n) for (int i = 0; i < int(n); ++i)
#define mkp(a, b) make_pair(a, b)
using namespace std;
typedef long long ll;
typedef long double ld;
typedef pair<int, int> PII;
typedef vector<int> VI;
typedef vector<PII> VPI;
typedef vector<VI> VVI;
typedef vector<VVI> VVVI;
typedef vector<VPI> VVPI;
typedef pair<ll, ll> PLL;
typedef vector<ll> VL;
typedef vector<PLL> VPL;
typedef vector<VL> VVL;
typedef vector<VVL> VVVL;
typedef vector<VPL> VVPL;
template<class T> T setmax(T& a, T b) {if (a < b) return a = b; return a;}
template<class T> T setmin(T& a, T b) {if (a < b) return a; return a = b;}
#include <ext/pb_ds/assoc_container.hpp>
using namespace __gnu_pbds;
template<class T>
using indset = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
typedef vector<char> VC;
typedef vector<VC> VVC;
typedef vector<bool> VB;
typedef vector<VB> VVB;
 
ll solve2(int n, int r1, int c1, int r2, int c2, VI a) {
    r1--, c1--, r2--, c2--;
    priority_queue<pair<ll, PII>> pq;
    map<PII, int> vis;
    map<PII, ll> dist;
    pq.push({0, {r1, c1}});
    while (pq.size()) {
        PII u = pq.top().ss;
        pq.pop();
        if (vis[u]) continue;
        vis[u] = true;
        vector<pair<PII, ll>> harevan;
        if (true) {
            auto[r, c] = u;
            if (r) {
                harevan.pb({{r-1, min(c, a[r-1])}, 1});
                if (c == 0) harevan.pb({{r-1, a[r-1]}, 1});
            }
            if (r != n-1) {
                harevan.pb({{r+1, min(c, a[r+1])}, 1});
                if (c == a[r]) harevan.pb({{r+1, 0}, 1});
            }
            harevan.pb({{r, a[r]}, a[r]-c});
            harevan.pb({{r, 0}, c});
        }
        for (auto[v, w] : harevan) {
            if (!dist.count(v) || dist[u] + w < dist[v]) {
                dist[v] = dist[u] + w;
                pq.push({-dist[v], v});
            }
        }
    }
    ll ans = 1e18;
    for (auto[u, d] : dist) {
        if (u.ff == r2) {
            /*cout << "Distance to (" << u.ff << ", " << u.ss << ") = " << d << endl;*/
            setmin(ans, 1ll * abs(u.ss - c2) + d);
        }
    }
    return ans;
}

ll solve1(int n, int r1, int c1, int r2, int c2, VI a) {
    r1--, c1--, r2--, c2--;
    VI ls, rs;
    ls = rs = VI(n);
    if (true) {
        stack<int> st;
        st = stack<int>();
        replr(i, 0, n-1) {
            while (st.size() && a[st.top()] >= a[i]) st.pop();
            if (st.size()) ls[i] = st.top();
            else ls[i] = -1;
            st.push(i);
        }
        st = stack<int>();
        reprl(i, n-1, 0) {
            while (st.size() && a[st.top()] >= a[i]) st.pop();
            if (st.size()) rs[i] = st.top();
            else rs[i] = n;
            st.push(i);
        }
    }
    VVPI gp(2*n+2);
    /*
     * [0, n-1] - leftmost cells
     * [n, 2n-1] - rightmost cells
     * 2n - starting cell
     * 2n+1 - ending cell
     */
    rep(u, n) {
        if (u) gp[u].pb({u-1+n, 1});
        if (u) gp[u].pb({u-1, 1});
        if (u != n-1) gp[u].pb({u+1, 1});
    }
    rep(u, n) {
        if (u != n-1) gp[u+n].pb({u+1, 1});
        if (ls[u] != -1) gp[u+n].pb({ls[u]+n, u-ls[u]});
        if (rs[u] != n) gp[u+n].pb({rs[u]+n, rs[u]-u});
    }
    rep(u, n) {
        gp[u].pb({u+n, a[u]});
        gp[u+n].pb({u, a[u]});
    }

    replr(r, r1, n-1) {
        if (a[r] < c1) {
            gp[2*n].pb({r+n, abs(r1-r)});
            break;
        }
        gp[2*n].pb({r, abs(r1-r) + (c1-0)});
        gp[2*n].pb({r+n, abs(r1-r) + (a[r]-c1)});
    }
    reprl(r, r1, 0) {
        if (a[r] < c1) {
            gp[2*n].pb({r+n, abs(r1-r)});
            break;
        }
        gp[2*n].pb({r, abs(r1-r) + (c1-0)});
        gp[2*n].pb({r+n, abs(r1-r) + (a[r]-c1)});
    }



    replr(r, r2, n-1) {
        gp[r].pb({2*n+1, abs(r2-r) + (c2-0)});
        gp[r+n].pb({2*n+1, abs(r2-r) + abs(a[r]-c2)});
        if (a[r] < c2) break;
    }
    reprl(r, r2, 0) {
        gp[r].pb({2*n+1, abs(r2-r) + (c2-0)});
        gp[r+n].pb({2*n+1, abs(r2-r) + abs(a[r]-c2)});
        if (a[r] < c2) break;
    }
    /*rep(u, n) {*/
    /*    cout << "FROM " << u << ": " << endl;*/
    /*    for (auto[v, w] : gp[u]) cout << "  TO " << v << " WITH WEIGHT " << w << endl;*/
    /*}*/
    /*rep(u, n) {*/
    /*    cout << "FROM " << u+n << ": " << endl;*/
    /*    for (auto[v, w] : gp[u+n]) cout << "  TO " << v << " WITH WEIGHT " << w << endl;*/
    /*}*/
    int N = 2*n+2;
    priority_queue<PLL> pq;
    VI vis(N);
    VL dist(N, 1e18);
    dist[2*n] = 0;
    pq.push({-dist[2*n], 2*n});
    while (pq.size()) {
        int u = pq.top().ss;
        pq.pop();
        if (vis[u]) continue;
        vis[u] = true;
        /*cout << "PROCESSING " << u << ", DISTANCE " << dist[u] << endl;*/
        for (auto[v, w] : gp[u]) {
            if (dist[u] + w < dist[v]) {
                dist[v] = dist[u] + w;
                pq.push({-dist[v], v});
            }
        }
    }
    /*rep(u, N) {*/
    /*    for (auto[v, w] : gp[u]) {*/
    /*        if (v == 2*n+1) {*/
    /*            cout << u << " " << v << " " << w << endl;*/
    /*        }*/
    /*    }*/
    /*}*/
    ll straight = abs(r1-r2) + abs(c1-c2);
    replr(i, min(r1, r2), max(r1, r2)) {
        if (a[i] < min(c1, c2)) {
            straight = 1e18;
        }
    }
    return min(straight, dist[2*n+1]);
}
 
void grader() {
    int n;
    cin >> n;
    int r1, c1, r2, c2;
    cin >> r1 >> c1 >> r2 >> c2;
    VI a(n);
    for (int& x : a) cin >> x;
    cout << solve1(n, r1, c1, r2, c2, a) << endl;
        /*ll ans1 = solve1(n, r1, c1, r2, c2, a);*/
        /*ll ans2 = solve2(n, r1, c1, r2, c2, a);*/
        /*cout << "ANSWERS: " << ans1 << " " << ans2 << endl;*/
    return;
    int t;
    cin >> t;
    while (t--) {
        mt19937 rng(chrono::steady_clock().now().time_since_epoch().count());
        int n = 2;
        VI a(n);
        for (int& x : a) x = rng()%10;
        int r1 = rng()%n+1;
        int c1 = rng()%(a[r1-1]+1)+1;
        int r2 = rng()%n+1;
        int c2 = rng()%(a[r2-1]+1)+1;

        cout << endl;
        cout << n << endl;
        cout << r1 << " " << c1 << endl;
        cout << r2 << " " << c2 << endl;
        for (int x : a) cout << x << " "; cout << endl;

        ll ans1 = solve1(n, r1, c1, r2, c2, a);
        ll ans2 = solve2(n, r1, c1, r2, c2, a);
        cout << "ANSWERS: " << ans1 << " " << ans2 << endl;
        if (ans1 != ans2) {
            rep(i, 100) cout << "VAX QU ";
            return;
        }
    }
}

int main() {
    ios_base::sync_with_stdio(false);
    cin.tie(NULL), cout.tie(NULL);
    /*freopen("mincross.in", "r", stdin); */
    /*freopen("test.out", "w", stdout); */
    int t = 1;
    /*cin >> t; */
    while (t--) grader();
}
 
 
 
 
 
 

컴파일 시 표준 에러 (stderr) 메시지

Main.cpp: In function 'll solve2(int, int, int, int, int, VI)':
Main.cpp:50:17: warning: structured bindings only available with '-std=c++17' or '-std=gnu++17'
   50 |             auto[r, c] = u;
      |                 ^
Main.cpp:62:18: warning: structured bindings only available with '-std=c++17' or '-std=gnu++17'
   62 |         for (auto[v, w] : harevan) {
      |                  ^
Main.cpp:70:14: warning: structured bindings only available with '-std=c++17' or '-std=gnu++17'
   70 |     for (auto[u, d] : dist) {
      |              ^
Main.cpp: In function 'll solve1(int, int, int, int, int, VI)':
Main.cpp:171:18: warning: structured bindings only available with '-std=c++17' or '-std=gnu++17'
  171 |         for (auto[v, w] : gp[u]) {
      |                  ^
Main.cpp: In function 'void grader()':
Main.cpp:222:9: warning: this 'for' clause does not guard... [-Wmisleading-indentation]
  222 |         for (int x : a) cout << x << " "; cout << endl;
      |         ^~~
Main.cpp:222:43: note: ...this statement, but the latter is misleadingly indented as if it were guarded by the 'for'
  222 |         for (int x : a) cout << x << " "; cout << endl;
      |                                           ^~~~

• Subtask 0: 0 / 0
• Subtask 1: 5 / 5
• Subtask 2: 0 / 14
• Subtask 3: 0 / 26
• Subtask 4: 11 / 11
• Subtask 5: 0 / 44