Submission #1045237

#TimeUsernameProblemLanguageResultExecution timeMemory
1045237ZicrusAliens (IOI16_aliens)C++17
0 / 100
1 ms348 KiB
#include <bits/stdc++.h> #include "aliens.h" using namespace std; typedef long long ll; ll n, m; vector<pair<ll, ll>> p; ll getVal(vector<ll> &dp, vector<ll> &k, ll &pen, int &i, int j) { if (j <= 0) return (p[i].first + p[0].second + 2 - m) * (p[i].first + p[0].second + 2 - m) + pen; j--; if (p[i].first + p[j+1].second + 2 - m > (p[i].first - p[j].first)) return (p[i].first + p[j+1].second + 2 - m) * (p[i].first - p[j].first) * 2 - (p[i].first - p[j].first) * (p[i].first - p[j].first) + pen + dp[j]; else return (p[i].first + p[j+1].second + 2 - m) * (p[i].first + p[j+1].second + 2 - m) + pen + dp[j]; } pair<ll, ll> solve(ll pen) { vector<ll> dp(n, 1ll << 62ll); vector<ll> k(n, 1); dp[0] = (p[0].first + p[0].second + 2 - m) * (p[0].first + p[0].second + 2 - m) + pen; for (int i = 1; i < n; i++) { ll left = 0, right = i; while (left < right-1) { ll mid = (left + right) / 2; ll val1 = getVal(dp, k, pen, i, mid); ll val2 = getVal(dp, k, pen, i, mid+1); ll valK1 = mid == 0 ? 1 : (k[mid-1] + 1); ll valK2 = k[mid] + 1; if (val1 < dp[i] || (val1 <= dp[i] && valK1 < k[i])) { dp[i] = val1; k[i] = valK1; } if (val2 < dp[i] || (val2 <= dp[i] && valK2 < k[i])) { dp[i] = val2; k[i] = valK2; left = mid + 1; } else { right = mid; } } ll mid = (left + right) / 2; ll val = getVal(dp, k, pen, i, mid); ll valK = mid == 0 ? 1 : (k[mid-1] + 1); if (val < dp[i] || (val <= dp[i] && valK < k[i])) { dp[i] = val; k[i] = valK; } } return {k[n-1], dp[n-1]}; } ll take_photos(int n1, int m1, int k, vector<int> r, vector<int> c) { // Sort and filter n = n1; m = m1; vector<pair<ll, ll>> prs(n); for (int i = 0; i < n; i++) { if (r[i] > c[i]) prs[i] = {r[i], m-1-c[i]}; else prs[i] = {c[i], m-1-r[i]}; } sort(prs.begin(), prs.end()); p.clear(); for (auto &e : prs) { while (!p.empty() && p.back().second <= e.second) p.pop_back(); p.push_back(e); } n = p.size(); // Solve ll left = 0, right = (ll)m * (ll)m; while (left < right) { ll mid = (left + right) / 2; pair<ll, ll> val = solve(mid); if (val.first > k) { left = mid + 1; } else { right = mid; } } pair<ll, ll> res = solve(left); return res.second - k*left; }
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