Submission #1044548

#	Time	Username	Problem	Language	Result	Execution time	Memory
1044548		idas	Vision Program (IOI19_vision)	C++17	26 / 100	10 ms	1644 KiB

vision

#include "vision.h"
#include "bits/stdc++.h"
#define FOR(i, begin, end) for(int i=(begin); i<(end); i++)
#define pb push_back
#define s second
#define f first

using namespace std;
typedef pair<int, int> pii;
typedef vector<int> vi;

const int MxN=210;
int h, w, k, g[MxN][MxN], l[2*MxN], r[2*MxN], l_sz, r_sz;

void construct_network(int H, int W, int K) {
    h=H; w=W; k=K;

    int in=0;
    FOR(i, 0, h) {
        FOR(j, 0, w) {
            g[i][j]=in++;
        }
    }

    in=0;
    for(int i=h-1; i>=0; i--) {
        int j=0;
        vi ar;
        FOR(k, 0, max(h, w)) {
            if(i+k>=h || j+k>=w) break;
            ar.pb(g[i+k][j+k]);
        }
        l[in++]=add_or(ar);
    }
    FOR(j, 1, w) {
        int i=0;
        vi ar;
        FOR(k, 0, max(h, w)) {
            if(i+k>=h || j+k>=w) break;
            ar.pb(g[i+k][j+k]);
        }
        l[in++]=add_or(ar);
    }
    l_sz=in;

    in=0;
    FOR(j, 0, w) {
        int i=0;
        vi ar;
        FOR(k, 0, max(h,w)) {
            if(i+k>=h || j-k<0) break;
            ar.pb(g[i+k][j-k]);
        }
        r[in++]=add_or(ar);
    }
    FOR(i, 1, h) {
        int j=w-1;
        vi ar;
        FOR(k, 0, max(h, w)) {
            if(i+k>=h || j-k<0) break;
            ar.pb(g[i+k][j-k]);
        }
        r[in++]=add_or(ar);
    }
    r_sz=in;

    vi tmp;
    FOR(i, 0, l_sz) {
        if(i+k>=l_sz) break;
        tmp.pb(add_and({l[i], l[i+k]}));
    }
    int l_ok=add_or(tmp);

    tmp.clear();
    FOR(i, 0, r_sz) {
        if(i+k>=r_sz) break;
        tmp.pb(add_and({r[i], r[i+k]}));
    }
    int r_ok=add_or(tmp);

    tmp.clear();
    FOR(i, 0, l_sz) {
        if(i+k>=l_sz) break;
        vi ins;
        FOR(j, i, i+k+1) {
            ins.pb(l[j]);
        }
        ins.pb(add_or(ins));
        tmp.pb(add_xor(ins));
    }
    int l_block=add_or(tmp);

    tmp.clear();
    FOR(i, 0, r_sz) {
        if(i+k>=r_sz) break;
        vi ins;
        FOR(j, i, i+k+1) {
            ins.pb(r[j]);
        }
        ins.pb(add_or(ins));
        tmp.pb(add_xor(ins));
    }
    int r_block=add_or(tmp);

    int x=add_and({l_ok, r_block}), y=add_and({r_ok, l_block});
    add_or({x, y});
}
/*
4 4 1
3 3 2 3
*/

• Subtask 1: 0 / 10
• Subtask 2: 0 / 11
• Subtask 3: 0 / 11
• Subtask 4: 0 / 15
• Subtask 5: 12 / 12
• Subtask 6: 0 / 8
• Subtask 7: 14 / 14
• Subtask 8: 0 / 19