# | 제출 시각 | 아이디 | 문제 | 언어 | 결과 | 실행 시간 | 메모리 |
---|---|---|---|---|---|---|---|
1044497 | Tsovak | COVID tests (CEOI24_covid) | C++17 | 143 ms | 600 KiB |
이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
// -------------------- Includes -------------------- //
#define _CRT_SECURE_NO_WARNINGS
#define _USE_MATH_DEFINES
#include <iostream>
#include <iomanip>
#include <cstdio>
#include <stdio.h>
#include <cstdlib>
#include <stdlib.h>
#include <array>
#include <string>
#include <cstring>
#include <algorithm>
#include <cmath>
#include <math.h>
#include <set>
#include <map>
#include <unordered_set>
#include <unordered_map>
#include <vector>
#include <stack>
#include <queue>
#include <deque>
#include <bitset>
#include <list>
#include <iterator>
#include <numeric>
#include <complex>
#include <tuple>
#include <utility>
#include <cassert>
#include <assert.h>
#include <climits>
#include <limits.h>
#include <ctime>
#include <time.h>
#include <random>
#include <chrono>
#include <fstream>
using namespace std;
// -------------------- Typedefs -------------------- //
typedef long long ll;
typedef unsigned long long ull;
typedef double db;
typedef long double ld;
// -------------------- Defines -------------------- //
#define pr pair
#define mpr make_pair
#define ff first
#define ss second
#define mset multiset
#define mmap multimap
#define uset unordered_set
#define umap unordered_map
#define umset unordered_multiset
#define ummap unordered_multimap
#define pqueue priority_queue
#define sz(x) (int((x).size()))
#define len(x) (int((x).length()))
#define all(x) (x).begin(), (x).end()
#define clr(x) (x).clear()
#define ft front
#define bk back
#define pf push_front
#define pb push_back
#define popf pop_front
#define popb pop_back
#define lb lower_bound
#define ub upper_bound
#define bs binary_search
// -------------------- Constants -------------------- //
const int MAX = int(1e9 + 5);
const ll MAXL = ll(1e18 + 5);
const ll MOD = ll(1e9 + 7);
const ll MOD2 = ll(998244353);
// -------------------- Solution -------------------- //
/// You may use:
// The number of students
int N;
// The probability any given student is positive
double P;
// This function performs a test on a subset of samples.
// Its argument is a vector of Booleans of length N,
// where the i-th element is true if the i-th sample should be added to the mix.
// It returns true if (and only if) at least one of the samples in the mix is positive.
bool test_students(std::vector<bool> mask) {
assert(mask.size() == (size_t)N);
std::string mask_str(N, ' ');
for (int i = 0; i < N; i++)
mask_str[i] = mask[i] ? '1' : '0';
printf("Q %s\n", mask_str.c_str());
fflush(stdout);
char answer;
scanf(" %c", &answer);
return answer == 'P';
}
/// You should implement:
// This function will be called once for each test instance.
// It should use test_students to determine which samples are positive.
// It must return a vector of Booleans of length N,
// where the i-th element is true if and only if the i-th sample is positive.
vector<bool> ans;
void calc(int tl, int tr)
{
//cout << tl << ' ' << tr << "\n";
if (tl == tr) {
ans.pb(1);
return;
}
int m = (tl + tr) / 2;
vector<bool> msk(N, 0);
for (int i = tl; i <= m; i++) msk[i - 1] = 1;
if (test_students(msk)) calc(tl, m);
else for (int i = tl; i <= m; i++) ans.pb(0);
for (int i = tl; i <= m; i++) msk[i - 1] = 0;
for (int i = m + 1; i <= tr; i++) msk[i - 1] = 1;
if (test_students(msk)) calc(m + 1, tr);
else for (int i = m + 1; i <= tr; i++) ans.pb(0);
return;
}
vector<bool> find_positive()
{
int i, j;
clr(ans);
int h = int(db(P * 1000.0));
int l, r;
//cout << h << "\n";
if (h<1 || h>N) assert(false);
int len = (N + h - 1) / h;
for (i = 1; i <= N; i += len) {
calc(i, i + len - 1);
}
if (i != N + 1) {
i -= len;
calc(i, N);
}
//if (sz(ans) != N) assert(false);
return ans;
}
int main()
{
int T;
scanf("%d %lf %d", &N, &P, &T);
// You may perform any extra initialization here.
for (int i = 0; i < T; i++) {
std::vector<bool> answer = find_positive();
assert(answer.size() == (size_t)N);
std::string answer_str(N, ' ');
for (int j = 0; j < N; j++)
answer_str[j] = answer[j] ? '1' : '0';
printf("A %s\n", answer_str.c_str());
fflush(stdout);
char verdict;
scanf(" %c", &verdict);
if (verdict == 'W')
exit(0);
}
return 0;
}
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