제출 #104283

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
104283		tmk	ICC (CEOI16_icc)	C++17	0 / 100	366 ms	760 KiB

icc

#include<bits/stdc++.h>
#include "icc.h"
using namespace std;
#ifndef d
#define d(...)
#endif
#define st first
#define nd second
#define pb push_back
#define siz(c) (int)(c).size()
#define all(c) (c).begin(), (c).end()
typedef long long LL;
typedef long double LD;
constexpr int INF=1e9+7;
constexpr LL INFL=1e18;
template<class L, class R> ostream &operator<<(ostream &os, pair<L,R> P) {
  return os << "(" << P.st << "," << P.nd << ")";
}

constexpr int maxn = 105;

using Component = vector<int>;

int n;
vector<Component> C;

vector<int> get_vertices(vector<int>& ind) {
	vector<int> ret;
	for(auto i:ind)
		for(auto x:C[i])
			ret.push_back(x);
	return ret;
}

int make_query(vector<int> l, vector<int> r) {
	return query(l.size(), r.size(), l.data(), r.data());
}

void merge(int a, int b) {
	auto f = [&](int x) {
		for(size_t i=0; i<C.size(); i++)
			if(find(all(C[i]), x) != C[i].end())
				return i;
		return C.size();
	};
	
	a = f(a), b = f(b);
	for(auto x:C[b])
		C[a].push_back(x);
	C[b] = C.back();
	C.pop_back();
}

void run(int _n) {
	n = _n;
	for(int i=1; i<=n; i++) {
		C.push_back({i});
	}
	
	// mt19937 rng(time(0));
	for(int _=0; _<n-1; _++) {
		vector<int> L, R, ind(C.size());
		iota(all(ind), 0);
		int half = ind.size() / 2;
		while(true) {
			shuffle(all(ind), mt19937(time(0)));
			L.assign(ind.begin(), ind.begin() + half);
			R.assign(ind.begin() + half, ind.end());
			if(make_query(get_vertices(L), get_vertices(R))) break;
		}
		
		L = get_vertices(L);
		R = get_vertices(R);
		
		auto it = L.begin(), it2 = L.end();
		while(it + 1 != it2) {
			auto s = it + distance(it, it2) / 2;
			if(make_query(vector<int>(it, s), R))
				it2 = s;
			else
				it = s;
		}
		
		int a = *it;
		
		it = R.begin(), it2 = R.end();
		while(it + 1 != it2) {
			auto s = it + distance(it, it2) / 2;
			if(make_query(vector<int>(it, s), L))
				it2 = s;
			else
				it = s;
		}
		
		int b = *it;
		
		setRoad(a, b);
		merge(a, b);
	}
}

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• Subtask 2: 0 / 11
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• Subtask 6: 0 / 10