Submission #1040923

#TimeUsernameProblemLanguageResultExecution timeMemory
1040923GrindMachineEvent Hopping 2 (JOI21_event2)C++17
32 / 100
3044 ms5776 KiB
#include <bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> using namespace std; using namespace __gnu_pbds; template<typename T> using Tree = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>; typedef long long int ll; typedef long double ld; typedef pair<int,int> pii; typedef pair<ll,ll> pll; #define fastio ios_base::sync_with_stdio(false); cin.tie(NULL) #define pb push_back #define endl '\n' #define sz(a) (int)a.size() #define setbits(x) __builtin_popcountll(x) #define ff first #define ss second #define conts continue #define ceil2(x,y) ((x+y-1)/(y)) #define all(a) a.begin(), a.end() #define rall(a) a.rbegin(), a.rend() #define yes cout << "Yes" << endl #define no cout << "No" << endl #define rep(i,n) for(int i = 0; i < n; ++i) #define rep1(i,n) for(int i = 1; i <= n; ++i) #define rev(i,s,e) for(int i = s; i >= e; --i) #define trav(i,a) for(auto &i : a) template<typename T> void amin(T &a, T b) { a = min(a,b); } template<typename T> void amax(T &a, T b) { a = max(a,b); } #ifdef LOCAL #include "debug.h" #else #define debug(...) 42 #endif /* read the solution a long time ago, remember some key ideas from there */ const int MOD = 1e9 + 7; const int N = 1e5 + 5; const int inf1 = int(1e9) + 5; const ll inf2 = ll(1e18) + 5; void solve(int test_case) { ll n,k; cin >> n >> k; vector<pll> a(n+5); rep1(i,n) cin >> a[i].ff >> a[i].ss; rep1(i,n) a[i].ss--; set<pll> st; st.insert({-inf1,-inf1}); auto ok = [&](ll l, ll r){ auto it1 = st.lower_bound({l+1,-1}); it1--; auto it2 = st.lower_bound({r+1,-1}); it2--; if(it1 != it2) return false; auto [lx,rx] = *it1; if((lx <= l and l <= rx) or (lx <= r and r <= rx)) return false; return true; }; vector<ll> ans; rep1(i,n){ if(sz(ans) == k) break; auto [l,r] = a[i]; if(!ok(l,r)) conts; st.insert({l,r}); vector<pll> segs; for(int j = i+1; j <= n; ++j){ auto [lx,rx] = a[j]; if(!ok(lx,rx)) conts; segs.pb({rx,lx}); } sort(all(segs)); ll prevr = -inf2; ll cnt = sz(st)-1; for(auto [rx,lx] : segs){ if(lx > prevr){ cnt++; prevr = rx; } } if(cnt >= k){ ans.pb(i); } else{ st.erase({l,r}); } } if(ans.empty()){ cout << -1 << endl; } else{ trav(x,ans) cout << x << endl; } } int main() { fastio; int t = 1; // cin >> t; rep1(i, t) { solve(i); } return 0; }
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