제출 #1037403

#제출 시각아이디문제언어결과실행 시간메모리
1037403mindiyakBoxes with souvenirs (IOI15_boxes)C++14
10 / 100
10 ms78696 KiB
#include "boxes.h"
#pragma GCC optimize("O1,O2,O3,Ofast,unroll-loops")
#include <bits/stdc++.h>
#include <string>
#include <iostream>
#include <cmath>
#include <numeric>
#include <limits>
using namespace std;
typedef long long ll;
typedef unsigned long long ull;
typedef long double ld;
typedef pair<int, int> pi;
typedef pair<int, int> pl;
typedef pair<ld, ld> pd;
typedef vector<int> vi;
typedef vector<bool> vb;
typedef vector<vector<int>> vvi;
typedef vector<ld> vd;
typedef vector<ll> vl;
typedef vector<pi> vpi;
typedef vector<pl> vpl;
#define FOR(i, a, b) for (int i = a; i < (b); i++)
#define F0R(i, a) for (int i = 0; i < (a); i++)
#define FORd(i, a, b) for (int i = (b)-1; i >= a; i--)
#define F0Rd(i, a) for (int i = (a)-1; i >= 0; i--)
#define trav(a, x) for (auto &a : x)
#define uid(a, b) uniform_int_distribution<int>(a, b)(rng)
#define len(x) (int)(x).size()
#define mp make_pair
#define pb push_back
#define F first
#define nl endl
#define S second
#define lb lower_bound
#define ub upper_bound
#define aint(x) x.begin(), x.end()
#define raint(x) x.rbegin(), x.rend()
#define ins insert
const int MOD = 1000000007;

int L;
vl arr(1e7+10,0);

ll dis(ll a,ll b){
    return min(abs(b-a),L-abs(b-a));
}

ll dis2(ll a,ll b){
    // return min(abs(b-a),dis(0,a)+dis(0,b));
    return abs(b-a);
}

long long delivery(int N, int K, int l, int p[]) {
    L = l;
    FOR(i,0,N){
        arr[i] = dis(p[i],0);
    }

    ll ans = LLONG_MAX;

    // FOR(K,1,k+1){
        FOR(j,0,K){
            ll temp = 0;
            int last = 0;

            if(j != 0){
                // cout << "A " << arr[0] << " " << arr[j-1] << " " << dis2(p[0],p[j-1]) << endl;
                temp += arr[0] + arr[j-1] + dis2(p[0],p[j-1]);
            }

            for(int i=j;i<N;i+=K){
                if(i+K-1 > N-1)break;
                last = i+K;
                // cout << "B " << arr[i] << " " << arr[i+K-1] << " " << dis2(p[i],p[i+K-1]) << endl;
                temp += arr[i] + arr[i+K-1] + dis2(p[i],p[i+K-1]);
            }

            if(last <= N-1){
                // cout << "C " << arr[N-1] << " " << arr[last] << " " << dis2(p[last],p[N-1]) << endl;
                temp += arr[N-1] + arr[last] + dis2(p[last],p[N-1]);
            }

            // cout << j << " " << temp << endl;
            ans = min(ans,temp);
        }
    // }

    return ans;
}
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