이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
#define st first
#define nd second
#define mp make_pair
#define pb push_back
#define inf 1000000000000007
#define N 1000005
using namespace std;
typedef long long ll;
ll n, k, xx, yy, top, ans, a[N], b[N], x[N], pre[N];
ll solve(int nn, int K, int *A, int *B){
k = K;
for(ll i = 0; i < nn; i++){
a[++n] = A[i];
xx += A[i];
}
for(ll i = 0; i < nn; i++)
a[++n] = A[i];
n = 0;
for(ll i = 0; i < nn; i++){
b[++n] = B[i];
yy += B[i];
}
ans = xx - yy;
for(ll i = 0; i < nn; i++)
b[++n] = B[i];
for(ll i = 1; i <= n; i++){
// cout << a[i] << " " << b[i] << endl;
x[i] = x[i - 1] + a[i];
pre[i] = pre[i - 1] + b[i];
}
//tanim
if(n != 1)
while(1){
ll mx = 0, bas = 0, son = 0;
for(ll i = 1; i <= n; i++)
for(ll j = i; j <= n; j++){
if(j + k - 1 <= n and j + k - 1 - i + 1 < n/2){
if(x[j] - x[i - 1] - (pre[j + k - 1] - pre[i - 1]) > mx){
mx = x[j] - x[i - 1] - (pre[j + k - 1] - pre[i - 1]);
bas = i;
son = j;
}
}
}
if(!mx)
break;
ll i = bas;
ll j = son;
// cout << i << " " << j << " "<< mx << endl;
for(ll y = i; y <= j; y++){
a[ (y - 1)%(n/2) + 1 ] = -inf;
a[ (y - 1)%(n/2) + 1 + (n/2)] = -inf;
}
for(ll y = i; y <= j + k - 1; y++){
b[ (y - 1)%(n/2) + 1 ] = inf;
b[ (y - 1)%(n/2) + 1 + (n/2)] = inf;
}
for(ll i = 1; i <= n; i++){
x[i] = x[i - 1] + a[i];
pre[i] = pre[i - 1] + b[i];
}
top += mx;
// if(rand()%10 == 0)
// break;
}
ans = max(ans, top);
return ans;
}
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