Submission #103402

#	Time	Username	Problem	Language	Result	Execution time	Memory
103402		RockyB	Wiring (IOI17_wiring)	C++17	30 / 100	208 ms	10696 KiB

wiring

/// In The Name Of God
 
#include <bits/stdc++.h>
 
#define f first
#define s second
 
#define pb push_back
#define pp pop_back
#define mp make_pair
 
#define sz(x) (int)x.size()
#define sqr(x) ((x) * 1ll * (x))
#define all(x) x.begin(), x.end()
 
#define rep(i, l, r) for (int i = (l); i <= (r); i++)
#define per(i, l, r) for (int i = (l); i >= (r); i--)
 
#define Kazakhstan ios_base :: sync_with_stdio(0), cin.tie(0), cout.tie(0);
 
#define nl '\n'
#define ioi exit(0);
 
typedef long long ll;
typedef long double ld;
typedef unsigned long long ull;
 
const int N = (int)4e5 + 7;
const int inf = (int)1e9 + 7;
const int mod = (int)1e9 + 7;
const ll linf = (ll)1e18 + 7;
 
const int dx[] = {-1, 0, 1, 0, 1, -1, -1, 1};
const int dy[] = {0, 1, 0, -1, 1, -1, 1, -1};
 
using namespace std;
 
int sz;
pair <ll, int> t[N];
ll dp[N], s[N];
int nxt[N];

ll get(int l, int r) {
	if (nxt[l] == -1) assert(0);
	int n, m;
	int id = nxt[l] - 1;
	n = id - l + 1;
	m = r - id;

	ll res = 0;
	res += t[id].f * (id - l + 1) - (s[id] - s[l - 1]);
	res += (s[r] - s[id]) - t[id + 1].f * (r - id);
	res += max(n, m) * (t[id + 1].f - t[id].f);
	return res;
}
ll min_total_length(vector <int> _r, vector <int> _b) {
	for (auto it : _r) t[++sz] = {it, 0};
	for (auto it : _b) t[++sz] = {it, 1};

	sort (t + 1, t + 1 + sz);
	rep(i, 1, sz) s[i] = s[i - 1] + t[i].f;

	{ /// calc next
		int pos[2] = {-1, -1};
		per(i, sz, 1) {
			int b = t[i].s;
			nxt[i] = pos[b ^ 1];
			pos[b] = i;
		}
	}
	//rep(i, 1, sz) cerr << t[i].f << ' ' << t[i].s << nl;
	//cerr << nl;
	//cerr << nl;
	memset(dp, 0x3f, sizeof(dp));
	dp[0] = 0;
	int cnt = 0, last = -1;
	int pos[2] = {-1, -1};
	int R = -1;
	rep(i, 1, sz) {
		if (t[i].s != last) {
			cnt = 1, last = t[i].s;
			R = nxt[i];
			if (nxt[R] == -1) R = sz;
			else R = nxt[R] - 1;
		}
		else ++cnt;

		if (pos[t[i].s ^ 1] != -1) { /// go to the left
			int j = pos[t[i].s ^ 1];
			ll sum = s[i] - s[j];
			dp[i] = min(dp[i], dp[i - 1] + t[i].f - t[j].f);
			dp[i] = min(dp[i], dp[j - 1] + sum - (ll)t[j].f * (i - j));
		}
		{ /// go to the right
			int id = -1;
			int cur = 0;
			if (nxt[i] == -1) continue;
			while (R - nxt[i] + 1 > nxt[i] - i) R--;
			//cerr << i << ' ' << nxt[i] << ' ' << R << nl;
			rep(j, max(nxt[i], R - 100), R) {
				dp[j] = min(dp[j], min(dp[i - 1], dp[i]) + get(i, j));
				if (id == -1) id = j;
				++cur;
					//if (cur > id - i) break;
			}
		}
		pos[t[i].s] = i;
	}
	return dp[sz];
}
 
#ifdef IOI2018
 
namespace read {
 
	void read() {
		int n, m;
		assert(2 == scanf("%d %d", &n, &m));
 
		vector<int> r(n), b(m);
		for(int i = 0; i < n; i++)
			assert(1 == scanf("%d", &r[i]));
		for(int i = 0; i < m; i++)
			assert(1 == scanf("%d", &b[i]));
 
		long long res = min_total_length(r, b);
		printf("%lld\n", res);
		ioi
	}
}
 
int main() {
	#ifdef IOI2018
		freopen ("in.txt", "r", stdin);
		freopen ("slow.out", "w", stdout);
	#endif
	read :: read();
	ioi
}
 
#endif

//// 000 111  111111111

• Subtask 1: 7 / 7
• Subtask 2: 13 / 13
• Subtask 3: 10 / 10
• Subtask 4: 0 / 25
• Subtask 5: 0 / 45