이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
//#pragma GCC optimize("O3,unroll-loops")
//#pragma GCC target("avx2,bmi,bmi2,lzcnt,popcnt")
#include<bits/stdc++.h>
using namespace std;
#define fi first
#define se second
#define pb push_back
#define ll long long
#define ii pair<int, int>
#define vi vector<int>
#define vll vector<ll>
#define vii vector<ii>
#define cd complex<double>
#define ld long double
#define all(x) (x).begin(), (x).end()
#define iii tuple<int, int, int>
const ll mod = 1e9 + 7;
const ll INF = 1e18L + 5;
const double PI = acos(-1);
const int block = 320;
const int N = 5e5;
int tc, tt = 1;
int n;
pair<ll, ll> a[N + 5];
ll f[N + 5];
void solve() {
cin>>n;
for(int i=1; i<=n; i++) cin>>a[i].fi>>a[i].se;
sort(a + 1, a + 1 + n);
for(int i=1; i<=n; i++) f[i] = f[i - 1] + a[i].se;
ll mx = 0, ans = a[1].se;
mx = a[1].fi - f[0];
for(int i=2; i<=n; i++) {
ans = max(ans, a[i].se);
ans = max(ans, f[i] - a[i].fi + mx);
mx = max(mx, a[i].fi - f[i - 1]);
}
cout<<ans;
}
signed main() {
ios_base::sync_with_stdio(0);
cin.tie(0); cout.tie(0);
for(tc=1; tc<=tt; tc++) solve();
cerr<<"\nTime elapsed: "<<1000.0*clock()/CLOCKS_PER_SEC<<" ms.\n";
return 0;
}
# | Verdict | Execution time | Memory | Grader output |
---|
Fetching results... |
# | Verdict | Execution time | Memory | Grader output |
---|
Fetching results... |
# | Verdict | Execution time | Memory | Grader output |
---|
Fetching results... |
# | Verdict | Execution time | Memory | Grader output |
---|
Fetching results... |