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답안 #1032620

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
1032620 2024-07-24T04:13:43 Z caterpillow Exam (eJOI20_exam) C++17
65 / 100
 96 ms 98900 KB 
#include <bits/stdc++.h>

using namespace std;

using db = long double;
using ll = long long;
using pl = pair<ll, ll>;
using pi = pair<int, int>;
#define vt vector
#define f first
#define s second
#define pb push_back
#define all(x) x.begin(), x.end() 
#define size(x) ((int) (x).size())
#define FOR(i, a, b) for (int i = (a); i < (b); i++)
#define ROF(i, a, b) for (int i = (b) - 1; i >= (a); i--)
#define F0R(i, b) FOR (i, 0, b)
#define endl '\n'
const ll INF = 1e18;
const int inf = 1e9;

template<typename... Args> // tuples
ostream& operator<<(ostream& os, tuple<Args...> t) { 
    apply([&](Args... args) { string dlm = "{"; ((os << dlm << args, dlm = ", "), ...); }, t);
    return os << "}";
}

template<typename T, typename V> // pairs
ostream& operator<<(ostream& os, pair<T, V> p) { return os << "{" << p.f << ", " << p.s << "}"; }

template<class T, class = decltype(begin(declval<T>()))> // iterables
typename enable_if<!is_same<T, string>::value, ostream&>::type operator<<(ostream& os, const T& v) {
    string dlm = "{";
    for (auto& i : v) os << dlm << i, dlm = ", ";
    return os << "}";  
}

template <typename T, typename... V>
void printer(string pfx, const char *names, T&& head, V&& ...tail) {
    int i = 0;
    while (names[i] && names[i] != ',') i++;
    constexpr bool is_str = is_same_v<decay_t<T>, const char*>;
    if (is_str) cerr << " " << head;
    else cerr << pfx, cerr.write(names, i) << " = " << head; 
    if constexpr (sizeof...(tail)) printer(is_str ? "" : ",", names + i + 1, tail...);
    else cerr << endl;
}

#ifdef LOCAL
#define dbg(...) printer(to_string(__LINE__) + ": ", #__VA_ARGS__, __VA_ARGS__)
#else
#define dbg(x...)
#define cerr if (0) std::cerr
#endif

tuple<int, vt<int>, vt<int>> read() {
    int n; cin >> n;
    vt<int> a(n), b(n), c;
    F0R (i, n) cin >> a[i], c.pb(a[i]);
    F0R (i, n) cin >> b[i], c.pb(b[i]);
    sort(all(c));
    c.erase(unique(all(c)), c.end());
    auto ord = [&] (int x) { return lower_bound(all(c), x) - c.begin(); };
    for (auto& x : a) x = ord(x);
    for (auto& x : b) x = ord(x);
    return {n, a, b};
}

/*

we need to figure out what final configurations of A are possible
a person's level can only increase

rules: 
    1. some dude's work will always be a continuous range
    2. some dude's work can only spread up to the next larger guy on either side
    3. left to right ordering must be the same

as long as final state assignments follow these, its possible to construct

subtask 2: B is equal
    sorted stack to find next larger element on either side of each student with level B
    sum ranges

subtask 4: elements of A are distinct
    if kid i was to pass, then we know who gave him their work
    let dp[i][j] be the max passes, only allowing the first i kids to spread their work, considering only the first j kids in the line

everything else: n <= 5000
    let dp[i][j] be the max value of assigning some work to the first j kids, using only the first i kids' work
    for each kid, they are allowed to "spread" their range up to the next larger element on either side
    for each prefix, starting from the first kid he can claim, find the new max value of the prefix, additionally allowing the kid to claim some suffix of it

*/

int n;
vt<int> a, b;

void solve3() {

}

void solve2() {

}

void solve1() {
    vt<vt<int>> dp(n + 1, vt<int>(n + 1)); // 1-indexed
    vt<pi> rng(n); // reachable range
    F0R (i, n) {
        int j = i;
        while (j < n && a[j] <= a[i]) j++;
        rng[i].s = j - 1;
        j = i;
        while (j >= 0 && a[j] <= a[i]) j--;
        rng[i].f = j + 1;
    }
    dbg(rng);

    // dp
    F0R (i, n) {
        dbg(dp[i]);
        F0R (j, n + 1) dp[i + 1][j] = dp[i][j];
        auto [l, r] = rng[i];
        int best = dp[i][l];
        FOR (j, l, r + 1) {
            best = max(best + (b[j] == a[i]), dp[i][j + 1]);
            dp[i + 1][j + 1] = best;
        }
    }
    cout << dp[n][n] << endl;
}

main() {
    cin.tie(0)->sync_with_stdio(0);
    
    tie(n, a, b) = read();
    if (n <= 5000) {
        solve1();
    } else {
        int v = b[0];
        bool is_same = true;
        FOR (i, 1, n) is_same &= b[i] == v;
        if (is_same) solve2();
        else solve3();
    }
}

Compilation message

exam.cpp:134:1: warning: ISO C++ forbids declaration of 'main' with no type [-Wreturn-type]
  134 | main() {
      | ^~~~

Subtask #1
14.0 / 14.0

# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 344 KB Output is correct
2 Correct 0 ms 344 KB Output is correct
3 Correct 0 ms 348 KB Output is correct
4 Correct 1 ms 348 KB Output is correct
5 Correct 0 ms 348 KB Output is correct
6 Correct 0 ms 348 KB Output is correct

Subtask #2
0 / 12.0

# 결과 실행 시간 메모리 Grader output
1 Correct 3 ms 4440 KB Output is correct
2 Incorrect 5 ms 1232 KB Output isn't correct
3 Halted 0 ms 0 KB -

Subtask #3
13.0 / 13.0

# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 344 KB Output is correct
2 Correct 1 ms 1372 KB Output is correct
3 Correct 13 ms 16288 KB Output is correct
4 Correct 71 ms 90916 KB Output is correct
5 Correct 77 ms 98652 KB Output is correct
6 Correct 77 ms 98900 KB Output is correct

Subtask #4
0 / 23.0

# 결과 실행 시간 메모리 Grader output
1 Incorrect 2 ms 608 KB Output isn't correct
2 Halted 0 ms 0 KB -

Subtask #5
16.0 / 16.0

# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 344 KB Output is correct
2 Correct 0 ms 344 KB Output is correct
3 Correct 0 ms 348 KB Output is correct
4 Correct 1 ms 348 KB Output is correct
5 Correct 0 ms 348 KB Output is correct
6 Correct 0 ms 348 KB Output is correct
7 Correct 0 ms 348 KB Output is correct
8 Correct 0 ms 348 KB Output is correct
9 Correct 0 ms 348 KB Output is correct
10 Correct 1 ms 604 KB Output is correct
11 Correct 1 ms 604 KB Output is correct
12 Correct 1 ms 604 KB Output is correct
13 Correct 0 ms 608 KB Output is correct
14 Correct 0 ms 604 KB Output is correct

Subtask #6
22.0 / 22.0

# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 344 KB Output is correct
2 Correct 0 ms 344 KB Output is correct
3 Correct 0 ms 348 KB Output is correct
4 Correct 1 ms 348 KB Output is correct
5 Correct 0 ms 348 KB Output is correct
6 Correct 0 ms 348 KB Output is correct
7 Correct 0 ms 344 KB Output is correct
8 Correct 1 ms 1372 KB Output is correct
9 Correct 13 ms 16288 KB Output is correct
10 Correct 71 ms 90916 KB Output is correct
11 Correct 77 ms 98652 KB Output is correct
12 Correct 77 ms 98900 KB Output is correct
13 Correct 0 ms 348 KB Output is correct
14 Correct 0 ms 348 KB Output is correct
15 Correct 0 ms 348 KB Output is correct
16 Correct 1 ms 604 KB Output is correct
17 Correct 1 ms 604 KB Output is correct
18 Correct 1 ms 604 KB Output is correct
19 Correct 0 ms 608 KB Output is correct
20 Correct 0 ms 604 KB Output is correct
21 Correct 1 ms 604 KB Output is correct
22 Correct 3 ms 4452 KB Output is correct
23 Correct 96 ms 98572 KB Output is correct
24 Correct 71 ms 98648 KB Output is correct
25 Correct 58 ms 98644 KB Output is correct
26 Correct 54 ms 98632 KB Output is correct
27 Correct 57 ms 98628 KB Output is correct
28 Correct 64 ms 98896 KB Output is correct
29 Correct 68 ms 98648 KB Output is correct
30 Correct 96 ms 98644 KB Output is correct
31 Correct 71 ms 98444 KB Output is correct
32 Correct 74 ms 98652 KB Output is correct