#include "split.h"
#include <bits/stdc++.h>
using namespace std;
using i32 = int;
#define int long long
#define len(x) (int)(x.size())
#define inf 1000'000'000'000'000'000LL
#define all(x) x.begin(), x.end()
#define low_bit(x) (x & (-x))
template<typename T>
using vec = vector<T>;
vector<i32> find_split(i32 n, i32 a, i32 b, i32 c, vector<i32> p, vector<i32> q) {
if (a == 1) {
vec<vec<int>> g(n);
for (int i = 0; i < len(p); i++) {
g[p[i]].push_back(q[i]);
g[q[i]].push_back(p[i]);
}
vec<i32> ans(n, -1);
vec<int> sizes(n);
int need = 0;
int T = 0;
vec<bool> used(n, false);
function<void(int, int)> choose = [&](int v, int p) {
if (need == 0)
return;
if (used[v]) return;
used[v] = true;
need--;
ans[v] = T;
for (auto u: g[v]) {
if (u == p) continue;
choose(u, v);
}
};
need = b;
T = 2;
choose(0, -1);
for (int i = 0; i < n; i++) {
if (ans[i] == -1) {
ans[i] = 1;
break;
}
}
for (int i = 0; i < n; i++) {
if (ans[i] == -1) {
ans[i] = 3;
}
}
return ans;
}
else{
vec<vec<int>> g(n);
for (int i = 0; i < len(p); i++) {
g[p[i]].push_back(q[i]);
g[q[i]].push_back(p[i]);
}
vec<i32> ans(n, 3);
vec<int> sizes(n);
vec<pair<i32, i32>> z = {{a, 1},
{b, 2},
{c, 3}};
sort(all(z));
a = z[0].first;
int ax = z[0].second;
b = z[1].first;
int bx = z[1].second;
int cx = z[2].second;
std::fill(ans.begin(), ans.end(), cx);
int splitter = -1;
int ps;
vec<int> SZ = {-1, -1};
vec<int> Tid = {-1, -1};
vec<bool> used1(n, false);
function<void(int, int)> calc_sizes = [&](int v, int p) {
sizes[v] = 1;
used1[v] = true;
for (auto u: g[v]) {
if (u == p) continue;
if (used1[u]) continue;
calc_sizes(u, v);
sizes[v] += sizes[u];
}
if (sizes[v] >= a and (n - sizes[v]) >= b) {
splitter = v;
SZ[0] = a;
SZ[1] = b;
ps = p;
Tid[0] = ax;
Tid[1] = bx;
}
if (sizes[v] >= b and (n - sizes[v]) >= a) {
splitter = v;
SZ[0] = b;
SZ[1] = a;
ps = p;
Tid[0] = bx;
Tid[1] = ax;
}
};
calc_sizes(0, -1);
if (splitter == -1) {
return vec<i32>(n, 0);
}
int need = 0;
int T = 0;
vec<bool> used(n, false);
function<void(int, int)> choose = [&](int v, int p) {
if (need == 0)
return;
if (used[v]) return;
used[v] = true;
need--;
ans[v] = T;
for (auto u: g[v]) {
if (u == p) continue;
choose(u, v);
}
};
need = SZ[0];
T = Tid[0];
choose(splitter, ps);
need = SZ[1];
T = Tid[1];
choose(0, -1);
return ans;
}
}
