제출 #1032151

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
1032151		Turkhuu	봉쇄 시간 (IOI23_closing)	C++17	0 / 100	1008 ms	16472 KiB

closing

#include "closing.h"
#include <bits/stdc++.h>
using namespace std;
using ll = long long;
int max_score(int N, int X, int Y, ll K, vector<int> U, vector<int> V, vector<int> W) {
    vector<ll> pfs(N);
    for (int i = 0; i < N - 1; i++) {
        pfs[i + 1] = pfs[i] + W[i];
    }
    auto dis = [&](int x, int y) {
        if (x > y) swap(x, y);
        return pfs[y] - pfs[x];
    };
    vector<ll> one(N), two(N), s1(N + 1), s2(N + 1);
    for (int i = 0; i < N; i++) {
        tie(one[i], two[i]) = minmax(dis(X, i), dis(Y, i));
        s1[i + 1] = s1[i] + one[i];
        s2[i + 1] = s2[i] + two[i];
    }
    int ans = 0;
    {
        auto a(one); sort(a.begin(), a.end());
        ll sum = 0; int cnt = 0;
        while (cnt < N && sum + a[cnt] <= K) sum += a[cnt++];
        ans = max(ans, cnt);
    }
    for (int i = 0; i <= Y; i++) {
        ll s = s1[N];
        int l = 0, r = N - 1;
        for (int j = i; j < N; j++) {
            s += two[j] - one[j];
            if (r < j) r++;
            while (s > K && (l < min(i, X) || r > max(j, Y))) {
                if (l < min(i, X) && (r == max(j, Y) || one[l] > one[r])) s -= one[l++];
                else s -= one[r--];
            }
            if (s > K) break;
            {
                int l1 = l, r1 = r;
                int l2 = i, r2 = j;
                assert(l1 <= r1);
                assert(l2 <= r2);
                assert(l1 <= min(X, l2) && r1 >= max(Y, r2));
                // assert(s2[r2 + 1] - s2[l2] + s1[l2] - s1[l1] + s1[r1 + 1] - s1[r2 + 1] <= K);
                ans = max(ans, r1 - l1 + 1 + r2 - l2 + 1);
            }
        }
    }
    for (int l2 = 0; l2 < N; l2++) {
        for (int r2 = l2; r2 < N; r2++) {
            for (int l1 = 0; l1 <= min(X, l2); l1++) {
                for (int r1 = max(Y, r2); r1 < N; r1++) {
                    if (s2[r2 + 1] - s2[l2] + s1[l2] - s1[l1] + s1[r1 + 1] - s1[r2 + 1] <= K) {
                        ans = max(ans, r1 - l1 + 1 + r2 - l2 + 1);
                    }
                }
            }
        }
    }
    return ans;
}

• Subtask 0: 0 / 0
• Subtask 1: 0 / 8
• Subtask 2: 0 / 9
• Subtask 3: 0 / 12
• Subtask 4: 0 / 14
• Subtask 5: 0 / 9
• Subtask 6: 0 / 11
• Subtask 7: 0 / 10
• Subtask 8: 0 / 10
• Subtask 9: 0 / 17