이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
using namespace std;
#pragma GCC optimize("O3")
#define endl '\n'
#define db double
#define ll __int128
#define int long long
#define pb push_back
#define fs first
#define sd second
#define Mod long(1e9 + 7)
#define all(x) x.begin(), x.end()
#define unvisited long(-1)
#define Eps double(1e-9)
#define _for(i, n) for(int i = 0; i < (n); i++)
#define dbg(x) cout << #x ": " << x << endl;
const int Max = 1e6 + 7, Inf = 1e9 + 7;
void print(bool x) { cout << (x ? "YES" : "NO") << endl; }
string tostring (__int128 x)
{
string ans = "";
while(x > 0)
{
ans += (x % 10 + '0');
x /= 10;
}
reverse(all(ans));
return ans;
}
void solve()
{
int n, d, t; cin >> n >> d >> t;
vector <int> v(n), s(n+1);
for(auto& u : v) cin >> u;
int ans = 0, sum = 0;
for(int i = 0; i < n; i++) {
int sum = v[i];
for(int j = i+1; j < n; j++){
sum++;
if(sum > t) break;
s[j] = 1;
}
}
vector <vector<vector<int>>> dp(n+1, vector <vector<int>>
(d+1, vector<int> ({ 0, -Inf })));
for(int i = 1; i <= n; i++){
for(int j = 0; j <= d; j++){
dp[i][j][0] = max(dp[i-1][j][0], dp[i-1][j][1]);
if(v[i-1] > t){
dp[i][j][1] = max(dp[i-1][j][1], ((j-s[i-1])>= 0 ? dp[i-1][j-s[i-1]][0] : -Inf)) + 1;
}
//cerr << i << " " << j << " " << dp[i][j][0] << " " << dp[i][j][1] << endl;
ans = max(ans, max(dp[i][j][0], dp[i][j][1]));
}
}
cout << n-ans << endl;
}
int32_t main()
{
ios_base::sync_with_stdio(0);
cin.tie(0);
int Q = 1; //cin >> Q;
while (Q--)
{
solve();
}
return 0;
}
컴파일 시 표준 에러 (stderr) 메시지
prison.cpp: In function 'void solve()':
prison.cpp:41:18: warning: unused variable 'sum' [-Wunused-variable]
41 | int ans = 0, sum = 0;
| ^~~
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