Submission #1029707

#	Time	Username	Problem	Language	Result	Execution time	Memory
1029707		Mr_Husanboy	Overtaking (IOI23_overtaking)	C++17	65 / 100	3517 ms	26200 KiB

overtaking

#include "overtaking.h"

#include <bits/stdc++.h>

using namespace std;

#define ff first
#define ss second
#define all(a) (a).begin(), (a).end()
#define ll long long

template<typename T>
int len(T &a){
    return a.size();
}

mt19937 rng(chrono::high_resolution_clock::now().time_since_epoch().count());
int n, m, x; 
vector<int> s, w;
vector<vector<ll>> t;
vector<vector<pair<ll, ll>>> sorted;



void init(int L, int N, std::vector<long long> T, std::vector<int> W, int X, int M, std::vector<int> S)
{
    n = N; m = M; x = X;
    s.resize(n), w.resize(n);
    vector<int> ind(n);
    iota(all(ind), 0);
    // sort(all(ind), [&](int i, int j){
    //     return W[i] > W[j];
    // });


    s = S;
    t.assign(n + 1, vector<ll>(m , 0));
    sorted.assign(n + 1, vector<pair<ll, ll>>(m));
    for(int i = 0; i < n; i ++){
        w[i] = W[ind[i]];
        t[i][0] = T[ind[i]];
    }
    
    for(int j = 0; j < m - 1; j ++){
        vector<int> id(n);
        iota(all(id), 0);
        sort(all(id), [&](int a, int b){
            if(t[a][j] == t[b][j]) return w[a] < w[b];
            return t[a][j] < t[b][j];
        });
        ll mx = 0;
        for(int i : id){
            t[i][j + 1] = max(t[i][j] + 1ll * (s[j + 1] - s[j]) * w[i], mx);

            mx = max(mx, t[i][j + 1]);
        }
        mx = 0;
        for(int i = 0; i < n; i ++){
            sorted[i][j].ff = t[id[i]][j];
            mx = max(mx, t[id[i]][j + 1]);
            sorted[i][j].ss = mx;
        }
    }
    // for(int i = 0; i < n; i ++){
    //     for(int j = 0; j < n; j ++){
    //         cout << t[i][j] << ' ';
    //     }cout << endl;
    // }
}

long long arrival_time(long long y)
{
    for(int j = 0; j < m - 1; j ++){
        int l = -1, r = n;
        while(r - l > 1){
            int mid = (l + r) / 2;
            if(sorted[mid][j].ff >= y){
                r = mid;
            }else l = mid;
        }
        y += 1ll * x * (s[j + 1] - s[j]);
        if(l != -1){
            y = max(y, sorted[l][j].ss);
        }
        //cout << y << endl;
    }
    return y;
}

• Subtask 0: 0 / 0
• Subtask 1: 9 / 9
• Subtask 2: 10 / 10
• Subtask 3: 20 / 20
• Subtask 4: 26 / 26
• Subtask 5: 0 / 35