Submission #1029343

#	Time	Username	Problem	Language	Result	Execution time	Memory
1029343		Minbaev	Luxury burrow (IZhO13_burrow)	C++17	0 / 100	0 ms	348 KiB

burrow

#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp> 
 
#pragma GCC target("avx,avx2,fma")
#pragma GCC optimize("Ofast,unroll-loops")
 
using namespace std;
using namespace __gnu_pbds;
 
#define pb push_back
#define all(x) x.begin(),x.end()
#define rall(x) x.rbegin(),x.rend()
#define f first
#define s second
#define int long long
#define pii pair<int,int>
#define ar array
 
template<class T>bool umax(T &a,T b){if(a<b){a=b;return true;}return false;}
template<class T>bool umin(T &a,T b){if(b<a){a=b;return true;}return false;}
 
typedef tree<int, null_type, less_equal<int>, rb_tree_tag,
 tree_order_statistics_node_update> ordered_set;
 
const int inf = 1e17 + 7;
const int mod = 1e9 + 7;
const int N = 3e5 + 5;
const int md = 998244353;

int binpow(int a, int b){
	if(b == 0)return 1;
	if(b % 2 == 0){
		int c = binpow(a,b/2);
		return (c*c)%mod;
	}
	return (binpow(a,b-1)*a)%mod;
}

int divi(int a, int b){
	return (a*(binpow(b,mod-2)))%mod;
}

int n,m,k;

void solve(){
	
	cin >> n >> m >> k;
	
	int arr[n+1][m+1];
	for(int i = 0;i<n;i++)
		for(int j = 0;j<m;j++)
			cin >> arr[i][j];
		
	int area = 0, ans = -1;
	int l = 1, r = 1e9;
	
	while(l<=r){
		int mid = (l+r)/2;
		
		int dp[n+1][m+1]{};
		for(int i = n-1;i>=0;i--)
			for(int j = 0;j<m;j++)
				if(arr[i][j] >= mid)dp[i][j] = dp[i+1][j] + 1;
		
		int mx = -1;
		for(int i = 0;i<n;i++){
			for(int j = 0;j<m;j++){
				if(dp[i][j] == 0)continue;
				int r = j, mn = dp[i][j];
				while(r < m && dp[i][r] > 0){
					umax(mx, (r-j+1)*mn);
					r += 1;
					umin(mn, dp[i][r]);
				}
				j = r - 1;
			}
		}
		//~ cout << mid << "\n";
		//~ for(int i = 0;i<n;i++){
			//~ for(int j = 0;j<m;j++){
				//~ cout << dp[i][j] << " ";
			//~ }
			//~ cout << "\n";
		//~ }
		//~ cout << "\n";
		if(mx >= k){
			l = mid + 1;
			area = mx;
			ans = mid;
		}
		else{
			r = mid - 1;
		}
	}
	
	cout << ans << " " << area << "\n";
	
	
	
}
/*
2
2
2 1
4
2 3 1 4

 */
 signed main()
{
//	freopen("seq.in", "r", stdin);
//  freopen("seq.out", "w", stdout);
	ios_base::sync_with_stdio(0);cin.tie(NULL);cout.tie(NULL);
	int tt=1;//cin>>tt;
	while(tt--)solve();
 
}
 

• Subtask 1: 0 / 100