Submission #1027486

#TimeUsernameProblemLanguageResultExecution timeMemory
1027486caterpillowFeast (NOI19_feast)C++17
100 / 100
92 ms12884 KiB
#include <bits/stdc++.h> using namespace std; using db = long double; using ll = long long; using pl = pair<ll, ll>; using pi = pair<int, int>; #define vt vector #define f first #define s second #define pb push_back #define all(x) x.begin(), x.end() #define size(x) ((int) (x).size()) #define FOR(i, a, b) for (int i = (a); i < (b); i++) #define ROF(i, a, b) for (int i = (b) - 1; i >= (a); i--) #define F0R(i, b) FOR (i, 0, b) #define endl '\n' const ll INF = 1e18; const int inf = 1e9; template<typename Tuple, size_t... Is> void print_tuple(const Tuple& t, index_sequence<Is...>) { ((cerr << (Is == 0 ? "{" : ", ") << get<Is>(t)), ...); cerr << "}"; } template<typename... Args> ostream& operator<<(ostream& os, const tuple<Args...>& t) { print_tuple(t, index_sequence_for<Args...>{}); return os; } ostream& operator<<(ostream& os, string& s) { for (char c : s) os << c; return os; } template<template<typename> class Container, typename T> ostream& operator<<(ostream& os, Container<T> o) { os << "{"; int g = size(o); for (auto i : o) os << i << ((--g) == 0 ? "" : ", "); os << "}"; return os; } template<typename T, typename V> ostream& operator<<(ostream& os, const pair<T, V> p) { os << "{" << p.f << ", " << p.s << "}"; return os; } template <typename T, typename... V> void printer(const char *names, T &&head, V &&...tail) { int i = 0; while (names[i] != '\0' && names[i] != ',') i++; constexpr bool is_str = is_same_v<decay_t<T>, const char*>; if constexpr (is_str) cerr << head; // ignore directly passed strings else cerr.write(names, i) << " = " << head; if constexpr (sizeof...(tail)) cerr << (is_str ? "" : ","), printer(names + i + 1, tail...); else cerr << endl; } #ifdef LOCAL #define dbg(...) std::cerr << __LINE__ << ": ", printer(#__VA_ARGS__, __VA_ARGS__) #else #define dbg(x...) #define cerr if (0) std::cerr #endif /* aliens trick dp[i] = max value of eating first i dishes dp[i] = min(dp[i - 1], max (j < i) dp[j] + sfx[j + 1] - sfx[i + 1]) */ ll n, k; vt<ll> a, sfx; // tiebreak by minimum # of arrays used pl check(ll penalty) { vt<pl> dp(n + 1); ll best = sfx[0], used = 0; F0R (i, n) { dp[i + 1] = dp[i]; if (best - sfx[i + 1] - penalty > dp[i + 1].f) { dp[i + 1] = {best - sfx[i + 1] - penalty, used + 1}; } else if (best - sfx[i + 1] - penalty == dp[i + 1].f && used + 1 < dp[i + 1].s) { dp[i + 1] = {best - sfx[i + 1] - penalty, used + 1}; } if (dp[i + 1].f + sfx[i + 1] > best) tie(best, used) = dp[i + 1], best += sfx[i + 1]; else if (dp[i + 1].f + sfx[i + 1] == best && used > dp[i + 1].s) tie(best, used) = dp[i + 1], best += sfx[i + 1]; } return dp[n]; } main() { cin.tie(0)->sync_with_stdio(0); cin >> n >> k; a.resize(n); sfx.resize(n + 1); F0R (i, n) cin >> a[i]; copy(all(a), sfx.begin()); ROF (i, 0, n) sfx[i] += sfx[i + 1]; // more penalty = fewer arrays // want to find smallest penalty such that <= k arrays ll lo = -1, hi = 1e12; while (hi - lo > 1) { ll m = (lo + hi) / 2; auto [cost, used] = check(m); if (used > k) lo = m; else hi = m; } auto [cost, used] = check(hi); ll ans = cost + hi * k; cout << ans << endl; }

Compilation message (stderr)

feast.cpp:101:1: warning: ISO C++ forbids declaration of 'main' with no type [-Wreturn-type]
  101 | main() {
      | ^~~~
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