Submission #1027222

#	Time	Username	Problem	Language	Result	Execution time	Memory
1027222		idkman	Sure Bet (CEOI17_sure)	C++17	0 / 100	1 ms	2396 KiB

sure

// #pragma GCC optimize("O3,unroll-loops")
// #pragma GCC target("avx2,bmi,bmi2,lzcnt,popcnt")
#include <bits/stdc++.h>
#define ll long long
#define For(i,a,b) for(ll  i=(a);i<=(b);i++)
#define Ford(i,a,b) for(ll  i=(a);i>=(b);i--)
#define pb push_back
#define all(x) x.begin(), x.end()
#define fi first
#define se second
#define endl "\n"
using namespace std;
int Dx[] = {0, 1, 0, -1, -1, -1, 1, 1};
int Dy[] = {-1, 0, 1, 0, 1, -1, 1, -1};
int dx[] = {0, 1, 0, -1};
int dy[] = {-1, 0, 1, 0};
const ll inf = 1000000000000000000;
const int N = 100000;
const int block_size = 300;
const ll MOD =  1e9 + 7; /* 998244353 */
const int LG = 18;
const int K = 20;	
const int M = 10000000;
ll nph(ll k, ll x) { return ((x >> k) & 1LL); }
#define ld double
ll n;
ld a[N+3],b[N+3], prea[N+3], preb[N+3];
bool cmp(ld a, ld b) {
	return a > b;
}
ld result(vector<ld> a, vector<ld> b) {
	ld sum1 = 0;
	for(auto x : a) sum1 += x;
	ld sum2 = 0;
	for(auto x : b) sum2 += x;
	return min(sum1, sum2) - 1.0 * (a.size() + b.size());
}
void Solve() { 
	cin>>n;
	ld ans = 0.0;
	For(i, 1, n) cin>>a[i]>>b[i];
	sort(a+1, a+n+1, cmp); sort(b+1, b+n+1, cmp);
	For(i, 1, n) prea[i] = prea[i-1] + a[i];
	For(i, 1, n) preb[i] = preb[i-1] + b[i];
	//For(i, 1, n) cout << preb[i] << endl;
	// pick biggest first first
	ll l = 1, r = 1;
	vector<ld> used1, used2;
	while(l <= n && r <= n) {
		ll amount = a[l]; amount--;
		if(amount == 0) break; // 1 2 3 4 5
		ld have = preb[r + amount - 1] - preb[r-1];
		have -= 1.0 * (amount + 1);
		if(have > 0) {
			used1.pb(a[l]);
			For(i, r, r+amount-1) used2.pb(b[i]);
			r += amount;
		}
		l++;
	}
	//for(auto x : used2) cout << x << " ";
	ans = max(ans, result(used1, used2));
	used1.clear(); used2.clear();
	For(i, 1, n) swap(a[i], b[i]);
	l = 1; r = 1;
	while(l <= n && r <= n) {
		ll amount = a[l]; amount--;
		if(amount == 0) break; // 1 2 3 4 5
		ld have = preb[r + amount - 1] - preb[r-1];
		have -= 1.0 * (amount + 1);
		if(have > 0) {
			used1.pb(a[l]);
			For(i, r, r+amount-1) used2.pb(b[i]);
			r += amount;
		}
		l++;
	}
	//for(auto x : used2) cout << x << " ";
	ans = max(ans, result(used1, used2));
	cout << fixed << setprecision(4) << ans;
}	

int main() {
    // freopen("AVGSEQ.INP", "r", stdin);
    // freopen("AVGSEQ.OUT", "w", stdout);
    ios_base::sync_with_stdio(0); 
    cin.tie(NULL); 
    cout.tie(NULL);
    int t = 1;
    //cin >> t; 
    while(t--) 
    	Solve();
}

• Subtask 1: 0 / 20
• Subtask 2: 0 / 40
• Subtask 3: 0 / 40