이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include "meetings.h"
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
typedef vector<int> vi;
typedef vector<vi> vii;
typedef pair<int,int> pi;
typedef vector<pi> pii;
typedef tuple<int,int,int> tii;
typedef vector<ll> li;
typedef vector<li> lii;
#define REP(i,a,b) for(int i=a;i<b;i++)
#define F first
#define S second
#define PB push_back
#define MP make_pair
#define LSOne(s) ((s)&(-s))
ll INF=1e18+10;
int inf=1e9+10;
ll M=1e9+7;
pi build(vi &st,vi &H,int x,int l,int r){
if(l==r){
if(H[l]==1)st[x]=1;
else st[x]=0;
return {st[x],st[x]};
}
int m=(l+r)/2;
pi a=build(st,H,2*x,l,m);
pi b=build(st,H,2*x+1,m+1,r);
st[x]=max(a.S+b.F,max(st[2*x],st[2*x+1]));
if(a.F==m-l+1&&b.S==r-m)return {a.F+b.S,a.F+b.S};
if(a.F==m-l+1)return {a.F+b.F,b.S};
if(b.S==r-m)return {a.F,a.S+b.S};
return {a.F,b.S};
}
int solve(vi &st,vi &H,int x,int l,int r,int a,int b){
if(a>b)return 0;
if(l==a&&b==r)return st[x];
int m=(l+r)/2;
return solve(st,H,2*x,l,m,a,min(b,m))+solve(st,H,2*x+1,m+1,r,max(a,m+1),b);
}
std::vector<long long> minimum_costs(std::vector<int> H, std::vector<int> L,
std::vector<int> R) {
int n=H.size();
int q=L.size();
li ans(q,INF);
if(n<=5000&&q<=5000){
lii a(n,li(n,0));
REP(i,0,n){
int k=H[i];
REP(j,i,n){
k=max(k,H[j]);
a[i][j]=k;
}
k=H[i];
for(int j=i;j>=0;j--){
k=max(k,H[j]);
a[i][j]=k;
}
}
REP(i,0,n){
REP(j,i+1,n)a[i][j]+=a[i][j-1];
for(int j=i-1;j>=0;j--)a[i][j]+=a[i][j+1];
}
//REP(i,0,n)cerr<<a[3][i]<<" ";
REP(i,0,q)REP(j,L[i],R[i]+1)ans[i]=min(ans[i],a[j][L[i]]+a[j][R[i]]-a[j][j]);
return ans;
}
vi st(4*n,0);
build(st,H,1,0,n-1);
REP(i,0,q){
int k=solve(st,H,1,0,n-1,L[i],R[i]);
ans[i]=(R[i]-L[i]+1)*2-k;
}
//for(auto u:st)cerr<<u<<" ";cerr<<"\n";
return ans;
}
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