제출 #1024902

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
1024902		mindiyak	Crocodile's Underground City (IOI11_crocodile)	C++14	100 / 100	326 ms	69056 KiB

crocodile

#include <bits/stdc++.h>
#include <string>
#include <iostream>
#include <cmath>
#include <numeric>
using namespace std;
typedef long long ll;
typedef unsigned long long ull;
typedef long double ld;
typedef pair<int, int> pi;
typedef pair<int, int> pl;
typedef pair<ld, ld> pd;
typedef vector<int> vi;
typedef vector<bool> vb;
typedef vector<vector<int>> vvi;
typedef vector<ld> vd;
typedef vector<long long> vl;
typedef vector<pi> vpi;
typedef vector<pl> vpl;
#define FOR(i, a, b) for (int i = a; i < (b); i++)
#define F0R(i, a) for (int i = 0; i < (a); i++)
#define FORd(i, a, b) for (int i = (b)-1; i >= a; i--)
#define F0Rd(i, a) for (int i = (a)-1; i >= 0; i--)
#define trav(a, x) for (auto &a : x)
#define uid(a, b) uniform_int_distribution<int>(a, b)(rng)
#define len(x) (int)(x).size()
#define mp make_pair
#define pb push_back
#define F first
#define nl endl
#define S second
#define lb lower_bound
#define ub upper_bound
#define aint(x) x.begin(), x.end()
#define raint(x) x.rbegin(), x.rend()
#define ins insert
const int MOD = 1000000007;

#include "crocodile.h"

vector<vpi> paths(1e5+6,vpi());

int travel_plan(int N, int M, int R[][2], int L[], int K, int P[])
{
  FOR(i,0,M){
    paths[R[i][0]].pb({R[i][1],L[i]});
    paths[R[i][1]].pb({R[i][0],L[i]});
  }

  vi visited(N,0);
  vl dist1(N,1e18);
  vl dist2(N,1e18);

  priority_queue<pair<ll,int>> pq;
  FOR(i,0,K){
    pq.push({0,P[i]});
    dist1[P[i]] = 0;
    dist2[P[i]] = 0;
  }

  while(!pq.empty()){
    int node = pq.top().S;
    ll dist = pq.top().F;
    pq.pop();
    // cout << node << " " << dist << endl;
    if(visited[node])continue;
    visited[node] = 1;
    for(auto edge:paths[node]){
      ll temp = -dist + edge.S;
      if(dist1[edge.F] > temp){
        dist2[edge.F] = dist1[edge.F];
        dist1[edge.F] = temp;
        pq.push({-dist2[edge.F],edge.F});
      }
      else if(dist2[edge.F] > temp){
        dist2[edge.F] = temp;
        pq.push({-dist2[edge.F],edge.F});
      }
    }
  }

  // FOR(i,0,N){
  //   cout << i << " " << dist[i] << endl;
  // }

  return dist2[0];
}

• Subtask 1: 46 / 46
• Subtask 2: 43 / 43
• Subtask 3: 11 / 11