Submission #1023878

#TimeUsernameProblemLanguageResultExecution timeMemory
1023878caterpillowBurza (COCI16_burza)C++17
0 / 160
342 ms508604 KiB
#include <bits/stdc++.h> #include <random> using namespace std; using ll = long long; using pl = pair<ll, ll>; using pi = pair<int, int>; #define vt vector #define f first #define s second #define pb push_back #define all(x) x.begin(), x.end() #define size(x) ((int) (x).size()) #define FOR(i, a, b) for (int i = (a); i < (b); i++) #define ROF(i, a, b) for (int i = (b) - 1; i >= (a); i--) #define F0R(i, b) FOR (i, 0, b) #define endl '\n' const ll INF = 1e18; const int inf = 1e9; template<template<typename> class Container, typename T> ostream& operator<<(ostream& os, Container<T> o) { os << "{"; int g = size(o); for (auto i : o) os << i << ((--g) == 0 ? "" : ", "); os << "}"; return os; } void _print() { cerr << "\n"; } template<typename T, typename ...V> void _print(T t, V... v) { cerr << t; if (sizeof...(v)) cerr << ", "; _print(v...); } #ifdef LOCAL #define dbg(x...) cerr << #x << " = "; _print(x); #else #define dbg(x...) #define cerr if (0) std::cerr #endif /* you want to stop the coin from taking a path of length k you only block off nodes at the same depth as the turn number ie you block off one of the immediate subtrees hence, you block off one node at depths 1, 2, 3, ... k take dfs order let dp[i][j][k] be the max # of depth k nodes u can block off considering the flattened array starting from index i if you take the current node (and its allowed) you split the range and take the sum of the dps in its next sibling (or next node, if non exists) otherwise, you go into the next node */ void sus_assert(bool pred) { if (!pred) while (1); } int n, k, t; vt<vt<int>> adj; vt<int> depth, pos, jump, val, rpos; vt<int> sfx; void dfs(int u, int p = -1) { pos[u] = t++; if (depth[u] == k) val[u] = 1; for (int v : adj[u]) { if (v == p) continue; depth[v] = depth[u] + 1; dfs(v, u); val[u] += val[v]; } jump[u] = t; } int memo[400][400][400]; int dp(int i, int l, int r) { if (i == n) return 0; if (l > r) return 0; if (memo[i][l][r] != -1) return memo[i][l][r]; int u = rpos[i]; // get the actual node index at this position int ans = 0; if (l <= depth[u] && depth[u] <= r) { // allowed to take yourself ans = val[u] + dp(jump[u], l, depth[u] - 1) + dp(jump[u], depth[u] + 1, r); } ans = max(ans, dp(i + 1, l, r)); assert(ans <= sfx[i]); return memo[i][l][r] = ans; } main() { cin.tie(0)->sync_with_stdio(0); cin >> n >> k; adj.resize(n); depth = pos = jump = val = rpos = vt<int>(n, 0); F0R (i, n - 1) { int u, v; cin >> u >> v; u--, v--; adj[u].pb(v); adj[v].pb(u); } dfs(0); F0R (i, n) rpos[pos[i]] = i; memset(memo, -1, sizeof(memo)); sfx.resize(n + 1); ROF (i, 0, n) sfx[i] += sfx[i + 1] + (depth[rpos[i]] == k); dbg(sfx); dbg(depth); dbg(pos); dbg(jump); dbg(val); dbg(rpos); // sanity check int cnt = 0; F0R (i, n) if (depth[i] == k) cnt++; sus_assert(val[0] == cnt); F0R (i, n) if (depth[i] > k) assert(val[i] == 0); int ans = dp(0, 1, k); dbg(ans); assert(ans <= val[0]); if (ans == val[0]) cout << "DA\n"; else cout << "NE\n"; }

Compilation message (stderr)

burza.cpp:103:1: warning: ISO C++ forbids declaration of 'main' with no type [-Wreturn-type]
  103 | main() {
      | ^~~~
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