Submission #1023283

#	Time	Username	Problem	Language	Result	Execution time	Memory
1023283		GrindMachine	Long Distance Coach (JOI17_coach)	C++17	71 / 100	2004 ms	15440 KiB

coach

#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>

using namespace std;
using namespace __gnu_pbds;

template<typename T> using Tree = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
typedef long long int ll;
typedef long double ld;
typedef pair<int,int> pii;
typedef pair<ll,ll> pll;

#define fastio ios_base::sync_with_stdio(false); cin.tie(NULL)
#define pb push_back
#define endl '\n'
#define sz(a) (int)a.size()
#define setbits(x) __builtin_popcountll(x)
#define ff first
#define ss second
#define conts continue
#define ceil2(x,y) ((x+y-1)/(y))
#define all(a) a.begin(), a.end()
#define rall(a) a.rbegin(), a.rend()
#define yes cout << "Yes" << endl
#define no cout << "No" << endl

#define rep(i,n) for(int i = 0; i < n; ++i)
#define rep1(i,n) for(int i = 1; i <= n; ++i)
#define rev(i,s,e) for(int i = s; i >= e; --i)
#define trav(i,a) for(auto &i : a)

template<typename T>
void amin(T &a, T b) {
    a = min(a,b);
}

template<typename T>
void amax(T &a, T b) {
    a = max(a,b);
}

#ifdef LOCAL
#include "debug.h"
#else
#define debug(...) 42
#endif

/*

refs:
edi

*/

const int MOD = 1e9 + 7;
const int N = 1e5 + 5;
const int inf1 = int(1e9) + 5;
const ll inf2 = ll(1e18) + 5;

// https://github.com/kth-competitive-programming/kactl/blob/main/content/data-structures/LineContainer.h
struct Line {
    mutable ll k, m, p;
    bool operator<(const Line& o) const { return k < o.k; }
    bool operator<(ll x) const { return p < x; }
};

struct LineContainer : multiset<Line, less<>> {
    // (for doubles, use inf = 1/.0, div(a,b) = a/b)
    static const ll inf = LLONG_MAX;
    ll div(ll a, ll b) { // floored division
        return a / b - ((a ^ b) < 0 && a % b);
    }
    bool isect(iterator x, iterator y) {
        if (y == end()) return x->p = inf, 0;
        if (x->k == y->k) x->p = x->m > y->m ? inf : -inf;
        else x->p = div(y->m - x->m, x->k - y->k);
        return x->p >= y->p;
    }
    void add(ll k, ll m) {
        k = -k, m = -m;
        auto z = insert({k, m, 0}), y = z++, x = y;
        while (isect(y, z)) z = erase(z);
        if (x != begin() && isect(--x, y)) isect(x, y = erase(y));
        while ((y = x) != begin() && (--x)->p >= y->p)
            isect(x, erase(y));
    }
    ll query(ll x) {
        assert(!empty());
        auto l = *lower_bound(x);
        return -(l.k * x + l.m);
    }
};

void solve(int test_case)
{
    ll X,n,m,W,T; cin >> X >> n >> m >> W >> T;
    vector<ll> a(n+1); // refilling points
    rep(i,n) cin >> a[i]; 
    a[n] = X;
    n++;

    auto cmp = [&](ll x, ll y){
        return x%T < y%T;
    };

    sort(all(a),cmp);

    vector<pll> b(m+1); // passengers
    rep1(i,m) cin >> b[i].ff >> b[i].ss;
    b[0] = {0,inf2};
    sort(all(b));
    m++;

    vector<ll> dp(m,inf2); // dp[i] = min cost for [0..i] if i is the last alive guy
    dp[0] = ((X-1)/T+1)*W;
    vector<ll> dp2(m,inf2);
    dp2[0] = dp[0];

    vector<ll> mnv(m,inf2);
    rep(i,m){
        ll l = b[i].ff, r = inf2;
        if(i+1 < m) r = b[i+1].ff;
        rep(j,n){
            if(l < a[j]%T and a[j]%T < r){
                amin(mnv[i],(a[j]/T)*W);
            }
        }
    }

    vector<ll> p(m);
    rep(i,m){
        p[i] = b[i].ss;
        if(i) p[i] += p[i-1];
    }

    LineContainer cht;
    cht.add(0,dp2[0]-p[0]);

    rep1(i,m-1){
        auto [d,c] = b[i];

        ll mul = mnv[i-1];

        if(mul < inf2){
            dp[i] = mul*(i-1)+p[i-1]+cht.query(mul);
        }
        else{
            ll j = i-1;
            dp[i] = mul*(i-j-1)+dp2[j]+p[i-1]-p[j];    
        }

        mul = mnv[i];

        if(mul < inf2){
            dp2[i] = mul*i+p[i]+cht.query(mul);
        }

        ll times = (X-d-1)/T+1;
        dp[i] += times*W;
        amin(dp2[i],dp[i]);

        cht.add(-i,dp2[i]-p[i]);
    }

    ll ans = dp2[m-1];
    cout << ans << endl;
}

int main()
{
    fastio;

    int t = 1;
    // cin >> t;

    rep1(i, t) {
        solve(i);
    }

    return 0;
}

• Subtask 1: 16 / 16
• Subtask 2: 30 / 30
• Subtask 3: 25 / 25
• Subtask 4: 0 / 29