이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
// In the name of Allah
#include <bits/stdc++.h>
#include "paint.h"
using namespace std;
typedef long long int ll;
typedef long double ld;
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;
typedef complex<ld> cld;
#define all(x) (x).begin(),(x).end()
#define len(x) ((ll) (x).size())
#define F first
#define S second
#define pb push_back
#define sep ' '
#define endl '\n'
#define Mp make_pair
#define kill(x) cout << x << '\n', exit(0)
#define set_dec(x) cout << fixed << setprecision(x);
#define file_io(x,y) freopen(x, "r", stdin); freopen(y, "w", stdout);
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
const int maxn = 2e5 + 7;
const int maxk = 100 + 4;
int n, k;
int A[maxn], val[maxk];
int sm0[maxn], sm1[maxn];
bool dp1[maxn][maxk], dp2[maxn][maxk];
int ok0[maxn], ok1[maxn];
string solve_puzzle(string s, vector<int> c) {
n = len(s); k = len(c);
for (int i = 1; i <= n; i++) {
if (s[i - 1] == 'X') A[i] = 1;
else if (s[i - 1] == '_') A[i] = 0;
else A[i] = -1;
sm0[i] = sm0[i - 1] + (A[i] == 0);
sm1[i] = sm1[i - 1] + (A[i] == 1);
}
for (int i = 1; i <= k; i++) val[i] = c[i - 1];
dp1[0][0] = 1;
for (int i = 1; i <= n; i++) {
for (int j = 0; j <= k; j++) {
if (A[i] != 1) dp1[i][j] = dp1[i - 1][j];
else dp1[i][j] = 0;
if (j >= 1 && i - val[j] >= 0) {
if (sm0[i] - sm0[i - val[j]] == 0) {
if (i - val[j] == 0) dp1[i][j] |= dp1[i - val[j]][j - 1];
else if (A[i - val[j]] != 1) dp1[i][j] |= dp1[i - val[j] - 1][j - 1];
}
}
}
}
dp2[n + 1][k + 1] = 1;
for (int i = n; i >= 1; i--) {
for (int j = k + 1; j >= 1; j--) {
if (A[i] != 1) dp2[i][j] = dp2[i + 1][j];
else dp2[i][j] = 0;
if (j <= k && i + val[j] - 1 <= n) {
if (sm0[i + val[j] - 1] - sm0[i - 1] == 0) {
if (i + val[j] == n + 1) dp2[i][j] |= dp2[i + val[j]][j + 1];
else if (A[i + val[j]] != 1) dp2[i][j] |= dp2[i + val[j] + 1][j + 1];
}
}
}
}
for (int i = 1; i <= n; i++) {
for (int j = 0; j <= k; j++) {
if (dp1[i - 1][j] && dp2[i + 1][j + 1]) {
ok0[i]++; ok0[i + 1]--;
}
}
}
for (int j = 1; j <= k; j++) {
for (int i = val[j]; i <= n; i++) {
if (sm0[i] - sm0[i - val[j]] != 0) continue;
if (i + 1 <= n && A[i + 1] == 1) continue;
if (i - val[j] >= 1 && A[i - val[j]] == 1) continue;
int j1 = max(i - val[j] - 1, 0);
int j2 = min(i + 2, n + 1);
if (dp1[j1][j - 1] && dp2[j2][j + 1]) {
ok1[i - val[j] + 1]++; ok1[i + 1]--;
}
}
}
string res = s;
for (int i = 1; i <= n; i++) {
ok0[i] += ok0[i - 1]; ok1[i] += ok1[i - 1];
if (res[i - 1] == '.') {
if (ok0[i] > 0 && ok1[i] > 0) res[i - 1] = '?';
else if (ok0[i] > 0) res[i - 1] = '_';
else res[i - 1] = 'X';
}
}
return res;
}
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