Submission #1022905

#	Time	Username	Problem	Language	Result	Execution time	Memory
1022905		shiomusubi496	Wiring (IOI17_wiring)	C++17	0 / 100	1031 ms	7096 KiB

wiring

#include "wiring.h"

#include <bits/stdc++.h>

#define rep(i, n) for (int i = 0; i < (int)(n); ++i)
#define rep2(i, a, b) for (int i = (int)(a); i < (int)(b); ++i)
#define rrep(i, n) for (int i = (int)(n) - 1; i >= 0; --i)
#define rrep2(i, a, b) for (int i = (int)(b) - 1; i >= (int)(a); --i)
#define all(v) begin(v), end(v)

using namespace std;

template<class T, class U> bool chmin(T& a, const U& b) { return a > b ? a = b, true : false; }
template<class T, class U> bool chmax(T& a, const U& b) { return a < b ? a = b, true : false; }

using ll = long long;

constexpr ll inf = 1e18;

long long min_total_length(std::vector<int> r, std::vector<int> b) {
    int N = r.size(), M = b.size();
    vector<pair<ll, int>> A(N + M);
    rep (i, N) A[i] = {r[i], 0};
    rep (i, M) A[N + i] = {b[i], 1};
    sort(all(A));
    vector<int> nxt(N + M + 1);
    nxt[N + M] = N + M;
    nxt[N + M - 1] = N + M;
    rrep (i, N + M - 1) {
        if (A[i].second == A[i + 1].second) nxt[i] = nxt[i + 1];
        else nxt[i] = i + 1;
    }
    vector<ll> dp(N + M + 1, inf);
    dp[0] = 0;
    rep (i, N + M) {
        int m = nxt[i];
        int r = nxt[m];
        if (m != r) {
            rep2 (j, m, r) {
                if (m - i >= r - m) {
                    ll sm = 0;
                    rep2 (k, i, m) sm += (A[k + 1].first - A[k].first) * (k - i + 1);
                    rep2 (k, m, j) sm += (A[k + 1].first - A[k].first) * (j - k);
                    chmin(dp[j + 1], dp[i] + sm);
                }
                else {
                    ll sm = 0;
                    rep2 (k, i, m - 1) sm += (A[k + 1].first - A[k].first) * (k - i + 1);
                    rep2 (k, m - 1, j) sm += (A[k + 1].first - A[k].first) * (j - k);
                    chmin(dp[j + 1], dp[i] + sm);
                }
            }
        }
        if (i != 0 && A[i].second != A[i - 1].second) {
            rep2 (j, i, m) {
                ll sm = 0;
                rep2 (k, i - 1, j) sm += (A[k + 1].first - A[k].first) * (j - k);
                chmin(dp[j + 1], dp[i] + sm);
            }
        }
    }
    return dp[N + M];
}

• Subtask 1: 0 / 7
• Subtask 2: 0 / 13
• Subtask 3: 0 / 10
• Subtask 4: 0 / 25
• Subtask 5: 0 / 45