Submission #1019677

#TimeUsernameProblemLanguageResultExecution timeMemory
1019677MinbaevK-th path (IZhO11_kthpath)C++17
0 / 100
1 ms348 KiB
#include <bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> #pragma GCC target("avx,avx2,fma") #pragma GCC optimize("Ofast,unroll-loops") using namespace std; using namespace __gnu_pbds; #define pb push_back #define all(x) x.begin(),x.end() #define rall(x) x.rbegin(),x.rend() #define f first #define s second #define int long long #define pii pair<int,int> template<class T>bool umax(T &a,T b){if(a<b){a=b;return true;}return false;} template<class T>bool umin(T &a,T b){if(b<a){a=b;return true;}return false;} template<class T> using Tree = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>; const int inf = 1e17 + 7; const int mod = 1e9 + 7; const int N = 3e5 + 5; int binpow(int a, int b){ if(b == 0)return 1; if(b % 2 == 0){ int c = binpow(a,b/2); return (c*c)%mod; } return (binpow(a,b-1)*a)%mod; } int divi(int a, int b){ return (a*(binpow(b,mod-2)))%mod; } int n,m,k; int cnk(int a, int b){ int a1 = 1; for(int i = a-b+1;i<=a;i++)a1 *= i; int b1 = 1; for(int i = 1;i<=b;i++)b1 *= i; return (int)a1/b1; } void solve(){ cin >> n >> m; char arr[35][35]; for(int i = 1;i<=n;i++){ for(int j = 1;j<=m;j++){ cin >> arr[i][j]; } } cin >> k; int sum = 0; vector<char>ans; ans.pb(arr[1][1]); int i = 1,j = 1; while(i < n && j < m){ if(arr[i+1][j] <= arr[i][j+1]){ if(sum + cnk(m+n-i-j-1, n-i-1) >= k){ ans .pb( arr[i+1][j]); i += 1; } else{ ans .pb( arr[i][j+1]); j += 1; sum += cnk(m+n-i-j-1, n-i-1); } } else{ if(sum + cnk(m+n-i-j-1, m-j-1) >= k){ ans .pb( arr[i][j+1]); j += 1; } else{ ans .pb( arr[i+1][j]); j += 1; sum += cnk(m+n-i-j-1, m-j-1); } } } while(i < n){ i += 1; ans .pb( arr[i][j]); } while(j < m){ j += 1; ans .pb( arr[i][j]); } for(auto to:ans)cout << to; } signed main() { // freopen("seq.in", "r", stdin); // freopen("seq.out", "w", stdout); ios_base::sync_with_stdio(0);cin.tie(NULL);cout.tie(NULL); int tt=1;//cin>>tt; while(tt--)solve(); }
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