Submission #1019196

#TimeUsernameProblemLanguageResultExecution timeMemory
1019196mindiyakRectangles (IOI19_rect)C++17
18 / 100
5070 ms500480 KiB
#include "rect.h" #include <bits/stdc++.h> #include <string> #include <iostream> #include <cmath> #include <numeric> using namespace std; typedef long long ll; typedef unsigned long long ull; typedef long double ld; typedef pair<int, int> pi; typedef pair<int, int> pl; typedef pair<ld, ld> pd; typedef vector<int> vi; typedef vector<bool> vb; typedef vector<vector<int>> vvi; typedef vector<ld> vd; typedef vector<long> vl; typedef vector<pi> vpi; typedef vector<pl> vpl; #define FOR(i, a, b) for (int i = a; i < (b); i++) #define F0R(i, a) for (int i = 0; i < (a); i++) #define FORd(i, a, b) for (int i = (b)-1; i >= a; i--) #define F0Rd(i, a) for (int i = (a)-1; i >= 0; i--) #define trav(a, x) for (auto &a : x) #define uid(a, b) uniform_int_distribution<int>(a, b)(rng) #define len(x) (int)(x).size() #define mp make_pair #define pb push_back #define F first #define nl endl #define S second #define lb lower_bound #define ub upper_bound #define aint(x) x.begin(), x.end() #define raint(x) x.rbegin(), x.rend() #define ins insert const int MOD = 1000000007; int N,M; vvi arr; ll ans = 0; set<pair<pi,pi>> visited; void dfs(int a,int b,int c,int d){ if(c<a)swap(a,c); if(d<b)swap(b,d); if(visited.count({{a,b},{c,d}}))return; if(a == 0 || b == 0 || c == (N-1) || d == (M-1))return; // cout << a << " " << b << " " << c << " " << d << endl; visited.insert({{a,b},{c,d}}); bool bad = false; FOR(i,a,c+1){ FOR(j,b,d+1){ // if(arr[i][j] >= arr[b-1][j])return; // if(arr[i][j] >= arr[d+1][j])return; // if(arr[i][j] >= arr[i][a-1])return; // if(arr[i][j] >= arr[i][c+1])return; if(arr[i][j] >= arr[i][b-1])bad = true; if(arr[i][j] >= arr[i][d+1])bad = true; if(arr[i][j] >= arr[a-1][j])bad = true; if(arr[i][j] >= arr[c+1][j])bad = true; if(bad)break; } } if(!bad)ans ++; dfs(a-1,b,c,d); dfs(a,b-1,c,d); dfs(a,b,c+1,d); dfs(a,b,c,d+1); } ll count_rectangles(vvi a) { N = a.size();M = a[0].size(); arr = a; FOR(i,1,N-1){ FOR(j,1,M-1){ dfs(i,j,i,j); } } return ans; }
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