제출 #1018417

#제출 시각아이디문제언어결과실행 시간메모리
1018417tinjyu추월 (IOI23_overtaking)C++17
9 / 100
7 ms39772 KiB
#include "overtaking.h" #include <algorithm> #include <iostream> using namespace std; long long int q, y, n, m, l, x; long long int t[1005][1005], T[1005], w[1005]; long long int s[1005]; class Time { public: long long int ti, speed, id; bool operator<(const Time &Ti) { if (ti != Ti.ti) return ti < Ti.ti; return speed < Ti.speed; } } prevtime[1005], sorted_time[1005][1005]; long long int pre_max_time[1005][1005]; void init(int L, int N, std::vector<long long> _T, std::vector<int> W, int X, int M, std::vector<int> S) { n = N; x = X; m = M; for (int i = 0; i < n; i++) { T[i] = _T[i]; w[i] = W[i]; t[i][0] = T[i]; prevtime[i].ti = T[i]; prevtime[i].speed = W[i]; prevtime[i].id = i; } for (int i = 0; i < m; i++) s[i] = S[i]; for (int i = 1; i < m; i++) { sort(prevtime, prevtime + n); long long int premax = 0; for (int j = 0; j < n; j++) { long long int nxttime = prevtime[j].ti + (S[i] - S[i - 1]) * prevtime[j].speed; t[i][prevtime[j].id] = max(premax, nxttime); premax = max(premax, t[i][prevtime[j].id]); } for (int j = 0; j < n; j++) { prevtime[j].ti = t[i][j]; prevtime[j].speed = W[j]; prevtime[j].id = j; } } for (int i = 0; i < m; i++) { for (int j = 0; j < n; j++) { sorted_time[i][j].ti = t[i][j]; sorted_time[i][j].speed = W[j]; sorted_time[i][j].id = j; } sort(sorted_time[i], sorted_time[i] + n); for (int j = 0; j < n; j++) { pre_max_time[i][j] = t[i + 1][sorted_time[i][j].id]; if (j != 0) pre_max_time[i][j] = max(pre_max_time[i][j], pre_max_time[i][j - 1]); // cout << i << " " << j << " " << pre_max_time[i][j] << " " << sorted_time[i][j].id << endl; } } return; } long long arrival_time(long long Y) { for (int i = 0; i < m - 1; i++) { Time now; now.ti = Y; now.speed = x; int l = 0, r = n - 1, tar = -1; while (l <= r) { int mid = (l + r) / 2; if (now < sorted_time[i][mid]) { r = mid - 1; } else { tar = mid; l = mid + 1; } } Y += (s[i + 1] - s[i]) * x; // cout << i << " " << tar << endl; if (tar != -1) { Y = max(Y, pre_max_time[i][tar]); } // cout << Y << endl; } return Y; }
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