제출 #1018106

#제출 시각아이디문제언어결과실행 시간메모리
1018106kym축구 경기장 (IOI23_soccer)C++17
48 / 100
23 ms12024 KiB
#include "soccer.h" #include <bits/stdc++.h> using namespace std; const int oo=1'000'000'000ll; int check(int n, vector<vector<int>> F) { int tot=0; for(int i=0;i<n;i++)for(int j=0;j<n;j++)tot+=F[i][j]==0; for(int j=0;j<n;j++){ // this checks every column fulfill the condition int stage=0; for(int i=0;i<n;i++){ if(stage==0){ if(F[i][j]==1)continue; else stage=1; } else if(stage==1){ if(F[i][j]==1)stage=2; else continue; } else if(stage==2){ if(F[i][j]==1)continue; else return 0; } } } for(int i=0;i<n;i++){ int stage=0; for(int j=0;j<n;j++){ if(stage==0){ if(F[i][j]==1)continue; else stage=1; } else if(stage==1){ if(F[i][j]==1)stage=2; else continue; } else if(stage==2){ if(F[i][j]==1)continue; else return 0; } } } vector<int> F1(n,oo); vector<int> L0(n,-1); for(int j=0;j<n;j++){ for(int i=0;i<n;i++){ if(F[i][j] == 0){ L0[j]=i; } else{ F1[j]=min(F1[j],i); } } } for(int i=0;i<n;i++){ vector<int> vec; for(int j=0;j<n;j++)if(F[i][j]==0){ vec.push_back(j); } if(vec.empty())continue; int st=vec[0], en=vec.back(); int worst=oo; for(int i=st;i<=en;i++){ worst=min(worst,L0[i]); } int best=0; for(int i=0;i<st;i++){ best=max(best,L0[i]); } for(int i=en+1;i<n;i++){ best=max(best,L0[i]); } if(best>worst){ return 0; } } return tot; } const int MAXN=31; int dp[MAXN][MAXN][MAXN][MAXN]; int biggest_stadium(int n, vector<vector<int>> F) { if(n==1){ if(F[0][0] == 0)return 1; else return 0; } int can=check(n,F); int ans=0; if(can)return can; for(int i=0;i<MAXN;i++)for(int j=0;j<MAXN;j++)for(int k=0;k<MAXN;k++)for(int z=0;z<MAXN;z++)dp[i][j][k][z]=-oo; for(int i=0;i<n;i++){ for(int j=0;j<n;j++){ for(int k=j;k<n;k++){ if(F[i][k]==1)break; dp[i][i][j][k]=k-j+1; ans=max(ans,k-j+1); } } } for(int i=n-1;i>=0;i--){ for(int j=i;j<=n-1;j++){ for(int x=0;x<n;x++){ for(int y=x;y<n;y++){ if(dp[i][j][x][y] == -oo)continue;//no way bro ans=max(ans,dp[i][j][x][y]); if(i!=0){ // try putting a thing at i-1 for(int nx=x;nx<=y;nx++){ for(int ny=nx;ny<=y;ny++){ if(F[i-1][ny] == 1)break; // cannot dp[i-1][j][nx][ny]=max(dp[i-1][j][nx][ny],dp[i][j][x][y]+(ny-nx+1)); ans=max(ans,dp[i-1][j][nx][ny]); } } } if(j!=n-1){ for(int nx=x;nx<=y;nx++){ for(int ny=nx;ny<=y;ny++){ if(F[j+1][ny] == 1)break; // cannot dp[i][j+1][nx][ny]=max(dp[i][j+1][nx][ny],dp[i][j][x][y]+(ny-nx+1)); ans=max(ans,dp[i][j+1][nx][ny]); } } } } } } } return ans; }
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