제출 #101801

#제출 시각아이디문제언어결과실행 시간메모리
101801briansuPaint By Numbers (IOI16_paint)C++14
100 / 100
365 ms91548 KiB
//{ #include<bits/stdc++.h> using namespace std; typedef long long ll; typedef double lf; typedef pair<ll,ll> ii; #define REP(i,n) for(ll i=0;i<n;i++) #define REP1(i,n) for(ll i=1;i<=n;i++) #define FILL(i,n) memset(i,n,sizeof i) #define X first #define Y second #define SZ(_a) (int)_a.size() #define ALL(_a) _a.begin(),_a.end() #define pb push_back #ifdef brian #define debug(...) do{\ fprintf(stderr,"%s - %d (%s) = ",__PRETTY_FUNCTION__,__LINE__,#__VA_ARGS__);\ _do(__VA_ARGS__);\ }while(0) template<typename T>void _do(T &&_x){cerr<<_x<<endl;} template<typename T,typename ...S> void _do(T &&_x,S &&..._t){cerr<<_x<<" ,";_do(_t...);} template<typename _a,typename _b> ostream& operator << (ostream &_s,const pair<_a,_b> &_p){return _s<<"("<<_p.X<<","<<_p.Y<<")";} template<typename It> ostream& _OUTC(ostream &_s,It _ita,It _itb) { _s<<"{"; for(It _it=_ita;_it!=_itb;_it++) { _s<<(_it==_ita?"":",")<<*_it; } _s<<"}"; return _s; } template<typename _a> ostream &operator << (ostream &_s,vector<_a> &_c){return _OUTC(_s,ALL(_c));} template<typename _a> ostream &operator << (ostream &_s,set<_a> &_c){return _OUTC(_s,ALL(_c));} template<typename _a,typename _b> ostream &operator << (ostream &_s,map<_a,_b> &_c){return _OUTC(_s,ALL(_c));} template<typename _t> void pary(_t _a,_t _b){_OUTC(cerr,_a,_b);cerr<<endl;} #define IOS() #else #define debug(...) #define pary(...) #define endl '\n' #define IOS() ios_base::sync_with_stdio(0);cin.tie(0); #endif // brian //} const ll MAXn=2e5+5,MAXlg=__lg(MAXn)+2; const ll MOD=1000000007; const ll INF=ll(1e15); #include "paint.h" ll d[MAXn], ans[MAXn]; ll pre[2][MAXn], h[MAXn], fw[MAXn]; bool dpf[MAXn][105][2], dpb[MAXn][105][2]; std::string solve_puzzle(std::string s, std::vector<int> c) { int n = SZ(s), k = SZ(c); REP(i,n) { if(s[i] == 'X')d[i+1] = 1; else if(s[i] == '_')d[i+1] = 0; else d[i+1] = -1; } REP1(i,n)if(d[i] != -1)pre[d[i]][i]++; REP(i,2)REP1(j, n)pre[i][j] += pre[i][j-1]; REP(i, k)h[i+1] = c[i]; dpf[0][0][0] = 1; REP1(i,n)REP(j,k+1) { // white if(d[i] != 1 && (dpf[i-1][j][1] || dpf[i-1][j][0]))dpf[i][j][0] = 1; // black if(j != 0)if(d[i] != 0 && i >= h[j] && pre[0][i] - pre[0][i - h[j]] == 0 && dpf[i - h[j]][j-1][0])dpf[i][j][1] = 1; } REP1(i,n)REP(j,k+1)debug(i, j, dpf[i][j][0], dpf[i][j][1]); dpb[n+1][k+1][0] = 1; for(int i = n;i > 0;i --)REP1(j, k+1) { // white if(d[i] != 1 && (dpb[i+1][j][1] || dpb[i+1][j][0]))dpb[i][j][0] = 1; // black if(j != k+1)if(d[i] != 0 && n - i + 1 >= h[j] && pre[0][i + h[j] - 1] - pre[0][i-1] == 0 && dpb[i + h[j]][j+1][0])dpb[i][j][1] = 1; } REP1(i,n)REP(j,k+1)debug(i, j, dpb[i][j][0], dpb[i][j][1]); FILL(ans, 0); // white REP1(i,n)REP(j, k+1)if(dpf[i][j][0] && dpb[i][j+1][0])ans[i] |= 1; //black FILL(fw, 0); REP1(i,n)REP1(j, k)if(i + h[j] - 1 <= n && dpf[i + h[j] - 1][j][1] && dpb[i][j][1])fw[i] = max(fw[i], h[j]); ll ct = 0; REP1(i, n) { ct = max(ct, fw[i]); if(ct > 0)ans[i] |= 2; ct --; } REP1(i,n)debug(i, fw[i], ans[i]); string as = ""; REP1(i,n) { if(ans[i] == 1)as.pb('_'); else if(ans[i] == 2)as.pb('X'); else as.pb('?'); } return as; }
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