Submission #1017860

#	Time	Username	Problem	Language	Result	Execution time	Memory
1017860		c2zi6	Split the Attractions (IOI19_split)	C++14	18 / 100	60 ms	14576 KiB

split

#define _USE_MATH_DEFINES
#include <bits/stdc++.h>
#define ff first
#define ss second
#define pb push_back
#define all(a) (a).begin(), (a).end()
#define replr(i, a, b) for (int i = int(a); i <= int(b); ++i)
#define reprl(i, a, b) for (int i = int(a); i >= int(b); --i)
#define rep(i, n) for (int i = 0; i < int(n); ++i)
#define mkp(a, b) make_pair(a, b)
using namespace std;
typedef long long ll;
typedef long double ld;
typedef pair<int, int> PII;
typedef vector<int> VI;
typedef vector<PII> VPI;
typedef vector<VI> VVI;
typedef vector<VVI> VVVI;
typedef vector<VPI> VVPI;
typedef pair<ll, ll> PLL;
typedef vector<ll> VL;
typedef vector<PLL> VPL;
typedef vector<VL> VVL;
typedef vector<VVL> VVVL;
typedef vector<VPL> VVPL;
template<class T> T setmax(T& a, T b) {if (a < b) return a = b; return a;}
template<class T> T setmin(T& a, T b) {if (a < b) return a; return a = b;}
#include <ext/pb_ds/assoc_container.hpp>
using namespace __gnu_pbds;
template<class T>
using indset = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
#include "split.h"

namespace TEST1 {
    bool check(int n, int A, int B, int C, VI P, VI Q) {
        int m = P.size();
        VI degree(n);
        rep(i, m) {
            degree[P[i]]++;
            degree[Q[i]]++;
        }
        for (int x : degree) if (x > 2) return false;
        return true;
    }
    VI find_split(int n, int A, int B, int C, VI U, VI V) {
        VVI gp(n);
        int m = U.size();
        rep(i, m) {
            gp[U[i]].pb(V[i]);
            gp[V[i]].pb(U[i]);
        }
        int st = -1;
        int nd = -1;
        rep(u, n) if (gp[u].size() == 1) {
            if (st == -1) st = u;
            else nd = u;
        }
        if (st == -1) {
            st = 0;
            nd = gp[0].back();
            gp[0].pop_back();
        }

        VI ans(n, 3);
        auto color = [&](int u, int cnt, int col) {
            int p = -1;
            while (cnt--) {
                ans[u] = col;
                for (int v : gp[u]) if (v != p) {
                    p = u;
                    u = v;
                    break;
                }
            }
            
        };
        color(st, A, 1);
        color(nd, B, 2);
        return ans;
    }
};
namespace TEST2 {
    int n;
    VVI gp;
    VI vis;
    VI ans;
    int cnt;
    void dfs(int u) {
        if (cnt == 0) return;
        ans[u] = 2;
        cnt--;
        vis[u] = true;
        for (int v : gp[u]) if (!vis[v]) {
            dfs(v);
        }
    }
    VI find_split(int N, int A, int B, int C, VI U, VI V) {
        n = N;
        gp = VVI(n);
        int m = U.size();
        rep(i, m) {
            gp[U[i]].pb(V[i]);
            gp[V[i]].pb(U[i]);
        }
        vis = VI(n);
        ans = VI(n, 3);
        cnt = B;
        dfs(0);
        rep(u, n) if (ans[u] == 3) {
            ans[u] = 1;
            break;
        }
        return ans;
    }
};

VI find_split(int n, int A, int B, int C, VI P, VI Q) {
    if (TEST1::check(n, A, B, C, P, Q)) return TEST1::find_split(n, A, B, C, P, Q);
    if (A == 1) return TEST2::find_split(n, A, B, C, P, Q);
	return {};
}

• Subtask 1: 7 / 7
• Subtask 2: 11 / 11
• Subtask 3: 0 / 22
• Subtask 4: 0 / 24
• Subtask 5: 0 / 36