Submission #1017661

#TimeUsernameProblemLanguageResultExecution timeMemory
1017661vjudge1Feast (NOI19_feast)C++17
100 / 100
83 ms18308 KiB
#include<bits/stdc++.h> using namespace std; #ifdef ONPC #include"debug.h" #else #define debug(...) 42 #endif #define endl '\n' #define ll long long #define pii pair<int,int> #define F first #define S second #define pb push_back #define sz(a) (int)a.size() #define all(a) a.begin(),a.end() #define int long long template<class T> bool ckmin(T& a, const T& b) { return b < a ? a = b, 1 : 0; } template<class T> bool ckmax(T& a, const T& b) { return a < b ? a = b, 1 : 0; } const int mod = 1e9 + 7; const int MAXN = 3e5 + 15; const int inf = 0x3f3f3f3f; const ll INF = 0x3f3f3f3f3f3f3f3f; int a[MAXN], n, k; int dp[4 * MAXN]; // i * 0 + 0, i * 0 + 1, i * 0 * 2, i * 0 + 3 char buf[1 << 25 | 1], *p1, *p2; #define gc() ((p1==p2)?(p2=(p1=buf)+fread(buf,1,1<<25,stdin),p1==p2?EOF:*p1++):*p1++) //#define gc() getchar() ll R(){ int x = 0, f = 0; char c = gc(); while (!isdigit(c)){ if (c == '-') f = 1; c = gc(); } while (isdigit(c)){ x = x * 10 + (c ^ 48); c = gc(); } return f ? -x : x; } pii solve(ll lampda){ dp[0 * 4 + 0] = 0; dp[0 * 4 + 1] = 0; dp[0 * 4 + 2] = -lampda; dp[0 * 4 + 3] = 1; for (int i = 1; i <= n; i++){ dp[i * 4 + 0] = max(dp[(i - 1) * 4 + 0], dp[(i - 1) * 4 + 2]); dp[i * 4 + 1] = (dp[(i - 1) * 4 + 0] > dp[(i - 1) * 4 + 2] ? dp[(i - 1) * 4 + 1] : dp[(i - 1) * 4 + 3]); dp[i * 4 + 2] = max(dp[(i - 1) * 4 + 0] + a[i] - lampda, dp[(i - 1) * 4 + 2] + a[i]); dp[i * 4 + 3] = (dp[(i - 1) * 4 + 0] + a[i] - lampda > dp[(i - 1) * 4 + 2] + a[i] ? dp[(i - 1) * 4 + 1] + 1 : dp[(i - 1) * 4 + 3]); //dp[i][0] = max(dp[i - 1][0], dp[i - 1][1]); //dp[i][1] = max(make_pair(dp[i - 1][0].F + a[i] - lampda, dp[i - 1][0].S + 1), //make_pair(dp[i - 1][1].F + a[i], dp[i - 1][1].S)); } return max(pii(dp[n * 4 + 0], dp[n * 4 + 1]), pii(dp[n * 4 + 2], dp[n * 4 + 3])); } int32_t main(){ n = R(), k = R(); //cin >> n >> k; for (int i = 1; i <= n; i++){ a[i] = R(); //cin >> a[i]; } ll lo = 0, hi = 1e14; while (hi - lo > 1){ ll mi = (lo + hi) >> 1; if (solve(mi).S >= k){ lo = mi; } else { hi = mi; } } cout << solve(lo).F + k * lo; }
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