제출 #1017521

#제출 시각아이디문제언어결과실행 시간메모리
1017521BestCrazyNoobRectangles (IOI19_rect)C++17
100 / 100
3444 ms419044 KiB
#include "rect.h" #include <utility> #include <tuple> #include <vector> #include <functional> #include <algorithm> using namespace std; using ll = long long; using pii = pair<int, int>; constexpr int MAXN = 2'500; int N, M; struct SegTreeMax { int sz; vector<pii> tree; // min, index (min(a, b) works) int ql, qr; void merge(int i) { tree[i] = max(tree[2*i], tree[2*i+1]); } SegTreeMax(vector<int> V) { sz = 1; while (sz < V.size()) sz *= 2; tree.resize(2*sz); for (int i = 0; i < V.size(); i++) tree[sz+i] = {V[i], i}; for (int i = V.size(); i < sz; i++) tree[sz+i] = {-1, -1}; for (int i = sz-1; i >= 1; i--) merge(i); } pii __query(int ni, int nl, int nr) { if (qr <= nl || nr <= ql) return {-1, -1}; if (ql <= nl && nr <= qr) return tree[ni]; int nm = (nl+nr)/2; return max(__query(2*ni, nl, nm), __query(2*ni+1, nm, nr)); } pii query(int l, int r) { ql = l; qr = r; return __query(1, 0, sz); } }; struct treap { treap *L, *R; int key, pri; int sz; treap() {} treap(int x): L(nullptr), R(nullptr), key(x), pri(rand()), sz(1) {} treap *join(treap *L, treap *R) { this->L = L; this->R = R; sz = 1+ (L ? L->sz : 0) + (R ? R->sz : 0); return this; } }; treap* merge(treap *L, treap *R) { if (!L) return R; if (!R) return L; if (L->pri > R->pri) { return L->join(L->L, merge(L->R, R)); } else { return R->join(merge(L, R->L), R->R); } } pair<treap*, treap*> split(treap *T, int x) { if (!T) return {nullptr, nullptr}; if (x <= T->key) { auto [LL, LR] = split(T->L, x); return {LL, T->join(LR, T->R)}; } else { auto [RL, RR] = split(T->R, x); return {T->join(T->L, RL), RR}; } } treap prealloc[10'000]; int nxtPrealloc; treap* insert(treap *T, int x) { auto [L, R] = split(T, x); prealloc[nxtPrealloc++] = treap(x); return merge(L, merge(prealloc + nxtPrealloc - 1, R)); } // 0 - excl ll query(treap *T, int r) { auto [L, R] = split(T, r); ll res = L ? L->sz : 0; T = merge(L, R); return res; } // excluded - excluded, because the last element on both sides is the border vector<pii> splits(vector<int> V) { // TODO: pay attention to equal elements. If there are multiples, return the rightmost. SegTreeMax seg(V); vector<pii> res; function<void(int, int, bool, bool)> rec = [&](int l, int r, bool lGood, bool rGood) { // Exit condition if (l == r) return; // Check that the extremes are actual elements if (l != 0 && r != V.size()) res.push_back({l-1, r}); if (l+1 == r) return; auto [mx, mxi] = seg.query(l, r); // rightmost max rec(mxi+1, r, true, rGood); int lastMxi = mxi; // iterate from right to left while (true) { auto [nxtMx, nxtMxi] = seg.query(l, lastMxi); if (nxtMx != mx) break; rec(nxtMxi+1, lastMxi, true, true); lastMxi = nxtMxi; } rec(l, lastMxi, lGood, true); }; rec(0, V.size(), false, false); return res; } long long count_rectangles(vector<vector<int>> a) { N = a.size(); M = a[0].size(); vector<vector<int>> a2(M, vector<int>(N)); vector<vector<vector<int>>> grid(N, vector<vector<int>>(M)); for (int i = 0; i < N; i++) { for (int j = 0; j < M; j++) { a2[j][i] = a[i][j]; } } for (int j = 0; j < M; j++) { for (auto [s, e]: splits(a2[j])) { grid[e][j].push_back(s); } } vector<vector<pii>> active(M, vector<pii>(M, {-2, -2})); // (incl, incl) long long ans = 0; for (int i = 1; i < N-1; i++) { vector<pii> x = splits(a[i]); vector<vector<int>> byEnd(M); vector<pii> cleanup; vector<pii> active2(N, {-2, -2}); for (auto[s, e]: x) { if (active[s][e].second == i-1) { // extend active[s][e].second = i; } else { // start again active[s][e] = {i, i}; } byEnd[e].push_back(s); } for (int j = 1; j < M; j++) { sort(grid[i+1][j-1].rbegin(), grid[i+1][j-1].rend()); sort(byEnd[j].begin(), byEnd[j].end(), [&](int a, int b) {return active[a][j].first > active[b][j].first;}); for (auto e: grid[i+1][j-1]) { // same idea as above if (active2[e].second == j-2) active2[e].second = j-1; else active2[e] = {j-1, j-1}; } nxtPrealloc = 0; // Treap prealloc treap* T = nullptr; for (int a = 0, b = 0; b < byEnd[j].size(); b++) { // TODO: might have to use a treap / sparse tree while (a < grid[i+1][j-1].size() && grid[i+1][j-1][a] >= active[byEnd[j][b]][j].first - 1) { T = insert(T, active2[grid[i+1][j-1][a]].first); a++; } for (int idx = 0; idx < a; idx++) { /* if (active2[grid[i+1][j-1][idx]].first <= byEnd[j][b]+1) { ans++; } */ } ans += query(T, byEnd[j][b]+2); // excluded } } } return ans; }

컴파일 시 표준 에러 (stderr) 메시지

rect.cpp: In constructor 'SegTreeMax::SegTreeMax(std::vector<int>)':
rect.cpp:24:13: warning: comparison of integer expressions of different signedness: 'int' and 'std::vector<int>::size_type' {aka 'long unsigned int'} [-Wsign-compare]
   24 |   while (sz < V.size()) sz *= 2;
      |          ~~~^~~~~~~~~~
rect.cpp:26:21: warning: comparison of integer expressions of different signedness: 'int' and 'std::vector<int>::size_type' {aka 'long unsigned int'} [-Wsign-compare]
   26 |   for (int i = 0; i < V.size(); i++) tree[sz+i] = {V[i], i};
      |                   ~~^~~~~~~~~~
rect.cpp: In lambda function:
rect.cpp:105:19: warning: comparison of integer expressions of different signedness: 'int' and 'std::vector<int>::size_type' {aka 'long unsigned int'} [-Wsign-compare]
  105 |   if (l != 0 && r != V.size()) res.push_back({l-1, r});
      |                 ~~^~~~~~~~~~~
rect.cpp: In function 'long long int count_rectangles(std::vector<std::vector<int> >)':
rect.cpp:165:29: warning: comparison of integer expressions of different signedness: 'int' and 'std::vector<int>::size_type' {aka 'long unsigned int'} [-Wsign-compare]
  165 |    for (int a = 0, b = 0; b < byEnd[j].size(); b++) {
      |                           ~~^~~~~~~~~~~~~~~~~
rect.cpp:167:14: warning: comparison of integer expressions of different signedness: 'int' and 'std::vector<int>::size_type' {aka 'long unsigned int'} [-Wsign-compare]
  167 |     while (a < grid[i+1][j-1].size() && grid[i+1][j-1][a] >= active[byEnd[j][b]][j].first - 1) {
      |            ~~^~~~~~~~~~~~~~~~~~~~~~~
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