제출 #1015510

#제출 시각아이디문제언어결과실행 시간메모리
1015510vjudge1새로운 문제 (POI11_met)C++17
74 / 100
2864 ms22864 KiB
#include <bits/stdc++.h> #include <fstream> #include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> #define endl '\n' #define pb push_back #define mod 1000000007 #define INF 100000000000000000 #define INF2 2000000000 #define fi first #define se second using namespace std; double const EPS = 1e-14; const int P = 1007; typedef long long ll; using namespace __gnu_pbds; typedef long long ll; typedef tree<int, null_type, less<int>, rb_tree_tag, tree_order_statistics_node_update> ordered_set; // find_by_order, order_of_key const int N = 3e5 + 4; int arr[N], tar[N], ans[N]; pair<int,int> rang[N]; struct Q { int l, r; ll val; }; Q query[N]; int main() { ios_base::sync_with_stdio(0); cout.tie(0); cin.tie(0); int n, m; cin >> n >> m; for(int i = 1; i <= m; i++) cin >> arr[i]; for(int i = 1; i <= n; i++) { cin >> tar[i]; ans[i] = -1; } int k; cin >> k; for(int i = 1; i <= k; i++) { int a, b; ll c; cin >> a >> b >> c; query[i].l = a; query[i].r = b; query[i].val = c; } for(int i = 1; i <= n; i++) { rang[i].fi = 1; rang[i].se = k; } while(true) { int mid[k+1] = {}; int where[n+1] = {}; ll cal[n+1] = {}; ll sum[m+2] = {}; bool ok = false; for(int i = 1; i <= n; i++) { if(rang[i].fi <= rang[i].se) { ll indx = (rang[i].fi+rang[i].se)/2; mid[indx]++; where[i] = indx; ok = true; } } if(!ok) break; for(int i = 1; i <= k; i++) { int l = query[i].l, r = query[i].r; ll val = query[i].val; if(l <= r) { sum[l] += val; sum[r+1] -= val; } else { sum[l] += val; sum[1] += val; sum[r+1] -= val; } if(mid[i] > 0) { ll cur[m+2] = {}; for(int j = 0; j < m+2; j++) cur[j] = sum[j]; for(int j = 1; j <= m; j++) { cur[j] += cur[j-1]; if(where[arr[j]] == i) { cal[arr[j]] += cur[j]; } } for(int j = 1; j <= n; j++) { //cout << i << 'a' << endl; //cout << j << ' ' << cal[j] << 'b' << endl; if(where[j] == i) { if(cal[j] >= tar[j]) { ans[j] = i; rang[j].se = i-1; } else { rang[j].fi = i+1; } } } } } } for(int i = 1; i <= n; i++) { if(ans[i] != -1) cout << ans[i] << endl; else cout << "NIE" << endl; } return 0; }
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