이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include<bits/stdc++.h>
using namespace std;
#define int long long
int n;
int a[200005];
int aint[530005][2];
void build(int nod, int st, int dr)
{
if(st==dr)
{
aint[nod][0] = 2*a[st]-a[st-1];
aint[nod][1] = a[st]-2*a[st-1];
return;
}
int mij=(st+dr)/2;
build(nod*2,st,mij);
build(nod*2+1,mij+1,dr);
aint[nod][0] = max(aint[nod*2][0], aint[nod*2+1][0]);
aint[nod][1] = max(aint[nod*2][1], aint[nod*2+1][1]);
}
int qry(int nod, int st, int dr, int le, int ri, int c)
{
if(le>ri)
return -1;
if(le==st && dr==ri)
return aint[nod][c];
int mij=(st+dr)/2;
return max(qry(nod*2,st,mij,le,min(mij,ri),c),
qry(nod*2+1,mij+1,dr,max(mij+1,le),ri,c));
}
int solve(int le, int ri, int poz)
{
if(le==1 && ri==n)
return 0;
if(le==1)
{
return a[n]-poz;
}
else if(ri==n)
{
return poz-a[1];
}
if(le>1 && (ri==n || poz-a[le-1] <= a[ri+1]-poz))///merge spre stanga
{
int st=2,dr=le,ans=le;
while(st<=dr)
{
int mij=(st+dr)/2;
if(qry(1,1,n,mij,le,0) <= a[ri+1])
{
ans=mij;
dr=mij-1;
}
else
st=mij+1;
}
return solve(ans-1,ri,a[ans-1]) + poz-a[ans-1];
}
else///merge spre dreapta
{
int st=ri+1,dr=n,ans=ri+1;
while(st<=dr)
{
int mij=(st+dr)/2;
if(qry(1,1,n,ri+1,mij,1) <= -a[le-1])
{
ans=mij;
st=mij+1;
}
else
dr=mij-1;
}
return solve(le,ans,a[ans]) + a[ans]-poz;
}
}
///a[x]-a[x-1] <= a[ri]-a[x]
///2*a[x]-a[x-1] <= a[ri]
///a[x]-a[x-1] <= a[x-1] - a[le]
///a[x]-2*a[x-1] <= -a[le]
signed main()
{
ios_base::sync_with_stdio(0);cin.tie(0);
cin>>n;
for(int i=1;i<=n;i++)
{
cin>>a[i];
}
build(1,1,n);
int q,s;
cin>>q;
while(q--)
{
cin>>s;
if(s<=a[1])
cout<<solve(1,1,a[1])+(a[1]-s)<<"\n";
else if(s>=a[n])
cout<<solve(n,n,a[n])+(s-a[n])<<"\n";
else
{
int st=1,dr=n-1,ans=n;
while(st<=dr)
{
int mij=(st+dr)/2;
if(a[mij]>=s)
{
ans=mij;
dr=mij-1;
}
else
st=mij+1;
}
if(ans==1 || a[ans]-s < s-a[ans-1]) cout<<solve(ans,ans,a[ans])+(a[ans]-s)<<"\n";
else cout<<solve(ans-1,ans-1,a[ans-1])+(s-a[ans-1])<<"\n";
}
}
return 0;
}
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