제출 #1013991

#제출 시각아이디문제언어결과실행 시간메모리
1013991vjudge1은행 (IZhO14_bank)C++17
100 / 100
145 ms8788 KiB
//#pragma GCC optimize("Ofast,O3,unroll-loops") //#pragma comment(linker, "/SET: 2000000") #include <bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> #define bp __builtin_popcountll #define mp make_pair #define pb push_back #define vec vector #define ll long long #define F first #define S second #define ld long double #define pii pair <int, int> #define elif else if #define sz(a) int32_t(a.size()) #define lb lower_bound #define ub upper_bound #define all(a) a.begin(), a.end() #define fl fflush(stdout) #define ex exit(0) #define pll pair <ll, ll> #define int ll #define FOR(i, l, r) for(int i = l; i <= r; ++i) #define ROF(i, l, r) for(int i = r; i >= l; --i) #define YES cout << "YES\n" #define NO cout << "NO\n" #define ti tuple<int, int, int> //#define FELIX using namespace std; using namespace __gnu_pbds; template <typename T> using ordered_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>; mt19937 rnd(228355); const int N = 21; const int M = (1 << N); int d[M], a[N], b[N], n, m; void solve(){ cin >> n >> m; FOR(i, 0, n - 1) cin >> a[i]; FOR(i, 0, m - 1) cin >> b[i]; FOR(i, 1, n - 1){ a[i] += a[i - 1]; } a[n] = 1e9; int mx = -1; int cur = (1 << m) - 1; //cout << "CUR: " << cur << "\n"; FOR(i, 0, cur){ int sum = 0; FOR(j, 0, m - 1){ int x = (1 << j); if((i & x)) sum += b[j]; } FOR(j, 0, m - 1){ int x = (1 << j); if(!(i & x)){ if(sum + b[j] == a[d[i]]){ d[i ^ x] = max(d[i ^ x], d[i] + 1); } if(sum + b[j] < a[d[i]]){ d[i ^ x] = max(d[i ^ x], d[i]); } } } mx = max(mx, d[i]); } if(mx == n) cout << "YES"; else cout << "NO"; } signed main(){ #ifdef FELIX auto _clock_start = chrono::high_resolution_clock::now(); #endif ios_base::sync_with_stdio(false); cin.tie(0); cout.tie(0); int t = 1; //cin >> t; while(t--) solve(); #ifdef FELIX cerr << "Executed in " << chrono::duration_cast<chrono::milliseconds>( chrono::high_resolution_clock::now() - _clock_start).count() << "ms." << endl; #endif }
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