제출 #1012714

#제출 시각아이디문제언어결과실행 시간메모리
1012714andrei_iorgulescu수열 (APIO14_sequence)C++14
100 / 100
1342 ms83276 KiB
#include <bits/stdc++.h> using namespace std; using integer = int; #define int long long int inf = 5e18; int n,k,a[100001]; int dp[100001],dpant[100001]; int f[100001]; integer ant[201][100001]; struct dreapta { int offset, panta; int eval(int x) { return offset + panta * x; } }; deque<pair<dreapta,integer>> dq; long double inters(dreapta d1, dreapta d2) { long double numarator = d2.offset - d1.offset,numitor = d1.panta - d2.panta; return numarator / numitor; } void update(dreapta d,int pos) { dq.push_back({d,pos}); while (dq.size() >= 2) { dreapta d1 = dq.back().first; int pos1 = dq.back().second; dq.pop_back(); dreapta d2 = dq.back().first; if (d1.panta != d2.panta) { dq.push_back({d1,pos1}); break; } else { int pos2 = dq.back().second; dq.pop_back(); if (d1.offset > d2.offset) dq.push_back({d1,pos1}); else dq.push_back({d2,pos2}); } } while (dq.size() >= 3) { dreapta d1 = dq.back().first; int pos1 = dq.back().second; dq.pop_back(); dreapta d2 = dq.back().first; int pos2 = dq.back().second; dq.pop_back(); dreapta d3 = dq.back().first; int pos3 = dq.back().second; dq.pop_back(); if (inters(d1,d2) >= inters(d2,d3)) { dq.push_back({d3,pos3}); dq.push_back({d1,pos1}); } else { dq.push_back({d3,pos3}); dq.push_back({d2,pos2}); dq.push_back({d1,pos1}); break; } } } int query(int x) { if (dq.empty()) return -inf; while (dq.size() >= 2) { dreapta d1 = dq.front().first; int pos1 = dq.front().second; dq.pop_front(); dreapta d2 = dq.front().first; if (d1.eval(x) > d2.eval(x)) { dq.push_front({d1,pos1}); break; } } return dq.front().first.eval(x); } signed main() { ios_base::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL); cin >> n >> k; for (int i = 1; i <= n; i++) cin >> a[i]; f[n] = a[n]; for (int i = n - 1; i >= 1; i--) f[i] = f[i + 1] + a[i]; dpant[1] = 0; for (int i = 2; i <= n; i++) dpant[i] = -inf; for (int j = 1; j <= k; j++) { dq.clear(); for (int i = 1; i <= n; i++) { dp[i] = query(f[i]) - f[i] * f[i]; if (!dq.empty()) ant[j][i] = dq.front().second; dreapta aux; aux.offset = dpant[i]; aux.panta = f[i]; update(aux,i); } for (int i = 1; i <= n; i++) dpant[i] = dp[i]; } int ans = 0; for (int i = k + 1; i <= n; i++) ans = max(ans,dp[i]); cout << ans << '\n'; int cine; for (int i = k + 1; i <= n; i++) if (dp[i] == ans) cine = i; vector<int> lol; for (int i = k; i >= 1; i--) { lol.push_back(cine - 1); cine = ant[i][cine]; } reverse(lol.begin(),lol.end()); for (auto it : lol) cout << it << ' '; return 0; } /* 7 3 4 1 3 4 0 2 3 */ /** Nu conteaza ordinea operatiilor, so dp[j][i] = facand j splituri pe locuri pana inainte de i (ultimul pe i), care e suma maxima pe care o pot obtine dp[j][i] = max(dp[j - 1][q < i] + f[i] * (f[q] - f[i])) f[i] = suma pe sufix de la i incolo deci am -f[i] * f[i] mereu, vreau maximul din dp[j - 1][q < i] + f[i] * f[q] Asta e evident CHT, cu update: dreapta dp[j - 1][i] cu panta f[i] si query in f[i] Query-urile sunt sortate descrescator si update-urile sunt tot descrescator dupa panta **/

컴파일 시 표준 에러 (stderr) 메시지

sequence.cpp: In function 'int main()':
sequence.cpp:144:28: warning: 'cine' may be used uninitialized in this function [-Wmaybe-uninitialized]
  144 |         lol.push_back(cine - 1);
      |                       ~~~~~^~~
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