제출 #1012232

#제출 시각아이디문제언어결과실행 시간메모리
1012232codefoxRobot (JOI21_ho_t4)C++14
0 / 100
3078 ms280492 KiB
#include<bits/stdc++.h>

using namespace std;

#pragma GCC optimize("Ofast")

#define int long long
#define arr array<int, 5>
#define pii pair<int, int>

vector<vector<arr>> graph;
vector<vector<int>> fc;
vector<int> d1;
vector<int> d2;
vector<int> d3;
vector<int> d4;


int32_t main()
{
    //freopen("input.txt", "r", stdin);
    //freopen("output.txt", "w", stdout);
    
    ios_base::sync_with_stdio(false);
    cin.tie(0);
    cout.tie(0);

    int n, m;
    cin >> n >> m;

    graph.assign(n, vector<arr>());
    vector<map<int, int>> cost(n);
    vector<map<int, int>> mn(n);
    vector<map<int, vector<pii>>> cc(n);
    fc.assign(n, vector<int>());
    d1.assign(n, 1e18);
    d2.assign(n, 1e18);
    d3.assign(n, 1e18);
    d4.assign(n, 1e18);

    for (int j = 0; j < m; j++)
    {
        int a, b, c, d;
        cin >> a >> b >> c >> d;
        a--; b--; c--;
        graph[a].push_back({b, c, d, 0, 0});
        graph[b].push_back({a, c, d, 0, 0});
    }

    for (int i = 0; i < n; i++)
    {
        for (arr ele:graph[i])
        {
            cost[i][ele[1]] += ele[2];
            mn[i][ele[1]] = 1e18;
            cc[i][ele[1]].push_back({ele[0], ele[2]});
        }
    }

    priority_queue<arr, vector<arr>, greater<arr>> pq;

    pq.push({0, 0, 0, -1, 0});
    pq.push({0, 1, 0, -1, 0});
    pq.push({0, 2, 0, -1, 0});
    pq.push({0, 3, 0, -1, 0});
    while (pq.size())
    {
        arr a = pq.top();
        pq.pop();
        int i = a[2];
        int c = a[1];
        int d = a[0];
        int p = a[3];
        int pc = a[4];
        if (pc == -1)
        {
            if (mn[i][c]<=d) continue;
            mn[i][c]=d;
            for (pii ele:cc[i][c])
            {
                pq.push({d, c, ele.first, p,0});
                pq.push({d+cost[ele.first][c]-ele.second, c, ele.first, p,-1});
            }
            continue;
        }
        if (d4[i]<=d) continue;
        int b = 0;
        for (int ele:fc[i])
        {
            if (ele ==c) b=1;
        }
        if (b) continue;
        fc[i].push_back(c);
        if (d1[i]==1e18) d1[i] = d;
        else if (d2[i]==1e18) d2[i] = d;
        else if (d3[i]==1e18) d3[i] = d;
        else if (d4[i]==1e18) d4[i] = d;
        int ava1 = -1;
        int ava2 = -1;
        int ava3 = -1;
        int avac1 = 0;
        int avac2 = 0;
        int avac3 = 0;
        for (int j = 0; j < m; j++)
        {
            if (cost[i][j]==0) 
            {
                if (ava1==-1) ava1 = j;
                else if (ava2==-1) ava2=j;
                else 
                {
                    ava3 = j;
                    break;
                }
            }
        }
        if (ava1==-1) avac1=1e18;
        if (ava2==-1) avac2=1e18;
        if (ava3==-1) avac3=1e18;
        for (arr ele:graph[i])
        {
            if (cost[i][ele[1]]<avac1)
            {
                ava3 = ava2;
                avac3 = avac2;
                ava2 = ava1;
                avac2 = avac1;
                avac1=cost[i][ele[1]];
                ava1=ele[1];
            }
            else if (cost[i][ele[1]]<avac2)
            {
                ava3 = ava2;
                avac3 = avac2;
                ava2 = ele[1];
                avac2=cost[i][ele[1]];
            }
            else if (cost[i][ele[1]]<avac3)
            {
                ava3=ele[1];
                avac3=cost[i][ele[1]];
            }
        }
        for (arr ele:graph[i])
        {
            if (ele[0]==p) continue;
            if (pc == ele[1]) pq.push({d+cost[i][ele[1]]-ele[2]+cost[ele[0]][ele[1]]-ele[2], ele[1], ele[0], i, -1});
            pq.push({d+cost[i][ele[1]]-ele[2], ele[1], ele[0], i, ele[1]});
            if (ava1!=-1) pq.push({d+ele[2]+avac1, ava1, ele[0], i, ele[1]});
            if (ava2!=-1) pq.push({d+ele[2]+avac2, ava2, ele[0], i, ele[1]});
            if (ava3!=-1) pq.push({d+ele[2]+avac3, ava3, ele[0], i, ele[1]});
        }
    }
    if (d1[n-1]>=1e18) cout << -1;
    else cout << d1[n-1];
    return 0;
}
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