제출 #1011950

#제출 시각아이디문제언어결과실행 시간메모리
1011950ProtonDecay314철로 (IOI14_rail)C++17
100 / 100
52 ms652 KiB
#include<bits/stdc++.h> using namespace std; typedef long long ll; typedef vector<ll> vll; typedef vector<vll> vvll; typedef vector<int> vi; typedef vector<vi> vvi; typedef pair<int, int> pi; typedef pair<ll, ll> pll; typedef vector<pi> vpi; typedef vector<pll> vpll; typedef vector<bool> vb; #define IOS ios_base::sync_with_stdio(false); cin.tie(nullptr); cout.tie(nullptr); #define L(varll, mn, mx) for(ll varll = (mn); varll < (mx); varll++) #define LR(varll, mx, mn) for(ll varll = (mx); varll > (mn); varll--) #define LI(vari, mn, mx) for(int vari = (mn); vari < (mx); vari++) #define LIR(vari, mx, mn) for(int vari = (mx); vari > (mn); vari--) #define INPV(varvec) for(auto& varveci : (varvec)) cin >> varveci #define fi first #define se second #define TCASES int t; cin >> t; while(t--) // #define DEBUG // #define AUTO_INTERACTOR #ifndef DEBUG #include "rail.h" #endif int n; #ifdef DEBUG vi a_loc; vi a_type; int getDistance(int i, int j) { #ifdef AUTO_INTERACTOR cout << i << " " << j << endl; int ans; int loc_i = a_loc[i], loc_j = a_loc[j]; if(loc_i > loc_j) { swap(loc_i, loc_j); swap(i, j); } // Now, i is to the left of j int typei = a_type[i], typej = a_type[j]; if(typei == 1 && typej == 2) { ans = loc_j - loc_i; } else if (typei == 1 && typej == 1) { // Find the leftmost D that is to the right of both int leftmost_d_pos = numeric_limits<int>::max(); LI(_i, 0, n) { if(a_loc[_i] > loc_j && a_type[_i] == 2 && a_loc[_i] < leftmost_d_pos) leftmost_d_pos = a_loc[_i]; } ans = (leftmost_d_pos << 1) - (loc_i + loc_j); } else if(typei == 2 && typej == 2) { // Find the rightmost C that is to the left of both int rightmost_c_pos = numeric_limits<int>::min(); LI(_i, 0, n) { if(a_loc[_i] < loc_i && a_type[_i] == 1 && a_loc[_i] > rightmost_c_pos) rightmost_c_pos = a_loc[_i]; } ans = (loc_i + loc_j) - (rightmost_c_pos << 1); } else { int leftmost_d_pos = numeric_limits<int>::max(); int rightmost_c_pos = numeric_limits<int>::min(); LI(_i, 0, n) { if(a_loc[_i] > loc_j && a_type[_i] == 2 && a_loc[_i] < leftmost_d_pos) leftmost_d_pos = a_loc[_i]; if(a_loc[_i] < loc_i && a_type[_i] == 1 && a_loc[_i] > rightmost_c_pos) rightmost_c_pos = a_loc[_i]; } ans = ((rightmost_c_pos - leftmost_d_pos) << 1) - (loc_j - loc_i); } cout << ans << endl; return ans; #endif #ifndef AUTO_INTERACTOR cout << i << " " << j << endl; int ans; cin >> ans; return ans; #endif } #endif void findLocation(int n, int first, int location[], int stype[]) { LI(i, 0, n) {stype[i] = 0; location[i] = -1;} location[0] = first; stype[0] = 1; if(n == 1) return; // Special case: if there's only one station, exit // Get the distances from station zero // Get the minimum distance, that will be a type 2 block vpi d0; d0.push_back({0, 0}); int stx = 0; int mindist0 = numeric_limits<int>::max(); LI(i, 1, n) { d0.push_back({getDistance(0, i), i}); if(d0[i].fi < mindist0) { mindist0 = d0[i].fi; stx = i; } } location[stx] = first + mindist0; stype[stx] = 2; vpi d0sorted = d0; sort(d0sorted.begin(), d0sorted.end()); // Getting distances from station X vpi dx; LI(i, 0, n) { if(i == stx) { dx.push_back({0, i}); continue; } dx.push_back({getDistance(stx, i), i}); } // Now we have ((--) /* (---)--(((--[(--]--)(--)) (---(--)-)[] */ int sty = stx; int styl = 0; // leftmost C-type LI(_i, 0, n) { int i = d0sorted[_i].se; if(i == 0 || i == stx) continue; if(dx[i].fi < dx[0].fi && d0[i].fi == d0[stx].fi + dx[i].fi) { // Station Z is between 0 and x location[i] = first + d0[stx].fi - dx[i].fi; stype[i] = 1; #ifdef DEBUG cout << "MIDCASE " << i << endl; #endif } else if(d0[i].fi == dx[i].fi + d0[stx].fi) { // Station Z is to the left of 0: literally just mirror the logic below int distzy = getDistance(i, styl); int deflect_st_block = location[styl] - ((dx[i].fi - dx[styl].fi - distzy) >> 1); int typeof_dst = 0; LI(j, 0, n) { if(location[j] == deflect_st_block) { typeof_dst = stype[j]; break; } } if(typeof_dst == 1) { // Deflector is of C-type, thus, the current station is // of type D location[i] = location[styl] + distzy; stype[i] = 2; } else { // Deflector is of D-type, thus the current station is of type C location[i] = first + dx[0].fi - dx[i].fi; stype[i] = 1; styl = i; } } else { // Station Z is to the right int distzy = getDistance(i, sty); int deflect_st_block = location[sty] + ((d0[i].fi - d0[sty].fi - distzy) >> 1); int typeof_dst = 0; LI(j, 0, n) { if(location[j] == deflect_st_block) { typeof_dst = stype[j]; break; } } if(typeof_dst == 2) { // Deflector is of D-type, thus, the current station is // of type C location[i] = location[sty] - distzy; stype[i] = 1; } else { // Deflector is of C-type, thus the current station is of type D location[i] = first + d0[i].fi; stype[i] = 2; sty = i; } } } // ok we're done! } #ifdef DEBUG int main() { cin >> n; #ifndef AUTO_INTERACTOR int first; cin >> first; #endif #ifdef AUTO_INTERACTOR LI(i, 0, n) { char c; int loc; cin >> c >> loc; a_type.push_back(c == 'C' ? 1 : 2); a_loc.push_back(loc); } #endif #ifdef AUTO_INTERACTOR int first = a_loc[0]; #endif vi location(n, 0); vi stype(n, 0); findLocation(n, first, &location[0], &stype[0]); cout << "THE ANSWER" << endl; L(i, 0, n) { #ifndef AUTO_INTERACTOR cout << i << " " << (stype[i] == 1 ? "C" : "D") << " " << location[i] << endl; #endif #ifdef AUTO_INTERACTOR cout << (stype[i] == 1 ? "C" : "D") << " " << location[i] << endl; #endif } return 0; } #endif
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