제출 #1011432

#제출 시각아이디문제언어결과실행 시간메모리
1011432GTACommuter Pass (JOI18_commuter_pass)C++17
100 / 100
285 ms29488 KiB
#include <bits/stdc++.h> using namespace std; #define int long long #define ll long long #define ld long double #define pb push_back #define endl '\n' #define all(v) v.begin(), v.end() #define all1(v) v.begin() + 1, v.end() #define rall(v) v.rbegin(), v.rend() #define rall1(v) v.rbegin(), v.rend()-1 #define fr(m,n,k) for(int m=n;m<=k;m++) #define frr(m,n,k) for(int m=n;m>=k;m--) #define yes cout << "YES" #define no cout << "NO" #define yesm cout << "Yes" #define nom cout << "No" #define inf 1e18 #define ext {cout << -1; return;} #define zxt {cout << 0; return;} #define noxt {no;return;} #define yesxt {yes;return;} #define gcd(a,b) __gcd(a,b) #define lcm(a,b) (a*(b/gcd(a,b))) #define fill(x,s) memset(x, s, sizeof(x)); #define lb lower_bound #define ub upper_bound #define pi pair<int,int> #define vi vector<int> #define vvi vector<vi> #define vs vector<string> #define vpi vector<pi> #define mii map<int,int> #define si set<int> #define fi first #define se second #define sz size() #define el cout<<endl int mod = 1e9 + 7; // int mod = 998244353; int ft(int n) {int ans = 1; for (int i = 1; i <= n; ++i) {ans = ans * i;} return ans;} int binpow(int x, int y) {if (y == 0) return 1; int z = 1; while (y) { if (y & 1) z = z * x % mod; x = x * x % mod; y >>= 1;} return z;} int inv(int x) {return binpow(x, mod - 2);} int bintoint(string s) {reverse(all(s)); int xx = 0; int m = 1; int z = s.sz; fr(j, 0, z) {xx += (s[j] == '1' ? m : 0); m <<= 1;} return xx;} string inttobin(int x) {if (x == 0) return "0"; string s; while (x) {s += (x & 1) + '0'; x >>= 1;} reverse(all(s)); return s;} string ads(string s, string p) {if (s.sz > p.sz) swap(s, p); int n = s.sz, m = p.sz; reverse(all(s)); reverse(all(p)); int tm = 0; string st; fr(i, 0, n - 1) {tm = s[i] - '0' + p[i] - '0' + tm; st += '0' + tm % 10; tm /= 10;} fr(i, n, m - 1) {tm = p[i] - '0' + tm; st += '0' + tm % 10; tm /= 10;} if (tm != 0) {st += '0' + tm % 10;} reverse(all(st)); return st;} bool id, id1, id2; int n, m, k, l, r, a, b, c, d, e, x, y, z, i, j, q, t, o; int mi = inf, ma, sum, ans, num, cnt; // string s, p; const int N = 1e5 + 5; vpi adj[N]; vi par[N]; //yg djikstra 0 dari u, 1 dari v int disu[N], disv[N], dis[N]; int s, u, v; void findis(int u, int disu[]) { priority_queue<array<int, 2>> pq; pq.push({ 0, u}); disu[u] = 0; while (pq.sz) { auto [jar, now] = pq.top(); pq.pop(); jar = -jar; if (disu[now] != jar) continue; for (auto [nx, w] : adj[now]) { int cur = jar + w; if (cur < disu[nx]) { disu[nx] = cur; pq.push({ -cur, nx}); } } } } void solve() { cin >> n >> m >> s >> t >> u >> v; fr(i, 1, m) { cin >> a >> b >> x; adj[a].pb({b, x}); adj[b].pb({a, x}); } fr(i, 1, n) dis[i] = inf, disu[i] = inf, disv[i] = inf; priority_queue<array<int, 2>> pq; pq.push({ 0, s}); dis[s] = 0; while (pq.sz) { auto [jar, now] = pq.top(); pq.pop(); jar = -jar; if (dis[now] != jar) continue; for (auto [nx, w] : adj[now]) { int cur = jar + w; if (cur < dis[nx]) { dis[nx] = cur; pq.push({ -cur, nx}); par[nx].clear(); } if (cur == dis[nx]) par[nx].pb(now); } } findis(u, disu); findis(v, disv); priority_queue<array<int, 4>> q; fr(i, 1, n) dis[i] = inf; dis[t] = disu[t] + disv[t]; q.push({ -dis[t], t, disu[t], disv[t]}); ans = inf; while (q.sz) { auto [jar, now, su, sv] = q.top(); q.pop(); jar = -jar; // cout << jar << " " << now << " " << su << " " << sv; el; if (dis[now] != jar) continue; if (now == s) { ans = min(ans, jar); continue; } for (auto nx : par[now]) { int cur = min(su, disu[nx]) + min(sv, disv[nx]); if (cur < dis[nx]) { dis[nx] = cur; q.push({ -cur, nx, min(su, disu[nx]), min(sv, disv[nx])}); } } } cout << min(ans, disu[v]); } signed main() { ios_base::sync_with_stdio(false); cin.tie(NULL); cout.tie(0); int T = 1; // cin >> T; for (; T--;) { cout << fixed << setprecision(5); solve(); if (T) cout << endl; } return 0; } // Tc, angka kecil), No Overthink(trivial tp modified), // Check Kasus Khusus(1,2,1e18), ganti jd bentuk lain (2 case or etc) // bedah 1 1 variable yg bisa dicari, cari dari jwbn ke ques // Sorting : Iterate Greedy (pake data struct) / dp / binser // Graphs / Tree : DFS / adj / dis[a][b] != dis[a][c] + dis[c][b] / indegree // Yang keliatan kyk dp : bisa jd brute force doang // Data Structure : BIT / DSU / Segtree, SparseT / dequeue // Compression, Line Sweep // Parity (2 or 3, mod 4..) klo dilakuin 2 kali jadi sama aja -> parity mod 2 /* brute force, greedy, pref sum, 2pointer, gcd/lcm, even/odd min/max, binser, bfs/dfs, iterate, multiple/divisor bipartite graph,bitmasking, sliding window, konstanta divconquer, djikstra, stack(prev and next smaller) prefix difference */ // tools : //__lg(x),__builtinpopcount,nextpermutation(), is_sorted / alpha / digit,
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