제출 #1011205

#제출 시각아이디문제언어결과실행 시간메모리
1011205huutuanFish 3 (JOI24_fish3)C++14
100 / 100
289 ms105988 KiB
#include<bits/stdc++.h> using namespace std; #define int long long struct Node{ int val, lazy; Node (int _val=0){ val=_val, lazy=LLONG_MAX; } Node operator+(const Node &b){ return Node(val+b.val); } }; struct SegmentTree{ int n; vector<Node> t; void init(int _n){ n=_n; t.assign(4*n+1, Node()); } void apply(int k, int l, int r, int val){ t[k].val=val*(r-l+1); t[k].lazy=val; } void push(int k, int l, int r){ if (t[k].lazy!=LLONG_MAX){ int mid=(l+r)>>1; apply(k<<1, l, mid, t[k].lazy); apply(k<<1|1, mid+1, r, t[k].lazy); t[k].lazy=LLONG_MAX; } } void update(int k, int l, int r, int L, int R, int val){ if (r<L || R<l) return; if (L<=l && r<=R){ apply(k, l, r, val); return; } push(k, l, r); int mid=(l+r)>>1; update(k<<1, l, mid, L, R, val); update(k<<1|1, mid+1, r, L, R, val); t[k]=t[k<<1]+t[k<<1|1]; } Node get(int k, int l, int r, int L, int R){ if (r<L || R<l) return t[0]; if (L<=l && r<=R) return t[k]; push(k, l, r); int mid=(l+r)>>1; return get(k<<1, l, mid, L, R)+get(k<<1|1, mid+1, r, L, R); } } seg; const int N=3e5+10, LG=19; int n, d, a[N], b[N], cnt[N], pf[N], ans[N], sp[LG][N], pfc[N]; vector<pair<int, int>> v[N]; int32_t main(){ ios_base::sync_with_stdio(false); cin.tie(nullptr); cin >> n >> d; for (int i=1; i<=n; ++i) cin >> a[i], b[i]=a[i]; for (int i=1, sum=0; i<=n; ++i){ b[i]-=sum; int mod=(b[i]%d+d)%d; b[i]-=mod; sum+=mod; cnt[i]=mod; sp[0][i]=b[i]; b[i]/=d; } for (int k=1; k<LG; ++k) for (int i=1; i+(1<<k)-1<=n; ++i) sp[k][i]=min(sp[k-1][i], sp[k-1][i+(1<<(k-1))]); partial_sum(b, b+n+1, pf); partial_sum(cnt, cnt+n+1, pfc); seg.init(n); int q; cin >> q; for (int i=1; i<=q; ++i){ int l, r; cin >> l >> r; v[r].emplace_back(l, i); } stack<int> st; for (int i=1; i<=n; ++i){ while (st.size() && b[i]<=b[st.top()]) st.pop(); seg.update(1, 1, n, st.empty()?1:st.top()+1, i, b[i]); st.push(i); for (auto &j:v[i]){ int l=j.first, id=j.second, r=i; if (l==r){ ans[id]=0; continue; } int lg=__lg(r-l); int cnt_l=a[l]%d; int min_val=min(sp[lg][l+1], sp[lg][r-(1<<lg)+1]); if (min_val+pfc[l]<cnt_l) ans[id]=-1; else{ int b_l=(a[l]-cnt_l)/d; ans[id]=pf[r]-pf[l]-seg.get(1, 1, n, l+1, r).val+b_l-min(b_l, (min_val+pfc[l]-cnt_l)/d); } } } for (int i=1; i<=q; ++i) cout << ans[i] << '\n'; return 0; }
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