이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
#define int ll
const int N = 2e5 + 7;
const int INF = 1e16;
int n, m, d;
int a[2 * N], b[2 * N];
struct Node {
ll mn;
ll mx;
ll diff;
Node() {
mn = INF;
mx = -INF;
diff = 0;
}
};
Node operator + (Node a, Node b) {
Node c;
c.mn = min(a.mn, b.mn);
c.mx = max(a.mx, b.mx);
c.diff = max(a.diff, b.diff);
c.diff = max(c.diff, b.mx - a.mn);
return c;
}
Node tree[8 * N];
pair<ll, ll> lazy[8 * N];
void push(int v, int tl, int tr) {
if (tl < tr) {
lazy[2 * v].first += lazy[v].first;
lazy[2 * v].second += lazy[v].second;
lazy[2 * v + 1].first += lazy[v].first;
lazy[2 * v + 1].second += lazy[v].second;
}
tree[v].mn += lazy[v].first;
tree[v].mx += lazy[v].second;
lazy[v] = {0, 0};
}
void add(int v, int tl, int tr, int l, int r, ll x, ll y) {
push(v, tl, tr);
if (l > tr || r < tl) {
return;
}
if (l <= tl && tr <= r) {
lazy[v].first += x;
lazy[v].second += y;
push(v, tl, tr);
return;
}
int tm = (tl + tr) / 2;
add(2 * v, tl, tm, l, r, x, y);
add(2 * v + 1, tm + 1, tr, l, r, x, y);
tree[v] = tree[2 * v] + tree[2 * v + 1];
}
Node get(int v, int tl, int tr, int l, int r) {
push(v, tl, tr);
if (l <= tl && tr <= r) {
return tree[v];
}
int tm = (tl + tr) / 2;
if (l <= tm && r <= tm) {
return get(2 * v, tl, tm, l, r);
} else if (tm + 1 <= l && tm + 1 <= r) {
return get(2 * v + 1, tm + 1, tr, l, r);
} else {
return get(2 * v, tl, tm, l, tm) + get(2 * v + 1, tm + 1, tr, tm + 1, r);
}
}
ll ans = 0;
void baga(int i) {
add(1, 1, n + m, b[i], b[i], -(INF + a[i]), INF - a[i]);
add(1, 1, n + m, b[i], n + m, d, d);
ans = get(1, 1, n + m, 1, n + m).diff;
}
signed main() {
ios::sync_with_stdio(false);
cin.tie(0);
cin >> n >> m >> d;
for (int i = 1; i <= n; ++i) {
cin >> a[i];
}
for (int i = 1; i <= m; ++i) {
cin >> a[i + n];
}
{
vector<pair<int, int>> v;
for (int i = 1; i <= n + m; ++i) v.push_back({a[i], i});
sort(v.begin(), v.end());
for (int i = 0; i < n + m; ++i) b[v[i].second] = i + 1;
}
for (int i = 1; i <= n; ++i) {
baga(i);
}
for (int i = 1; i <= m; ++i) {
baga(i + n);
cout << ans / 2;
if (ans % 2 == 1) cout << ".5";
cout << " ";
}
return 0;
}
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