제출 #1009949

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
1009949		stdfloat	벽 (IOI14_wall)	C++17	61 / 100	1301 ms	262144 KiB

wall

#include <bits/stdc++.h>
#include "wall.h"
using namespace std;

#define ff  first
#define ss  second
#define pii pair<int, int>

vector<int> st;

vector<vector<pii>> lz;

void Lz(int nd, pii p) {
	for (int i = (int)lz[nd].size() - 1; i >= 0; i--)
		if ((lz[nd][i].ff == 1 && p.ff == 1 && lz[nd][i].ss <= p.ss) || (lz[nd][i].ff == 2 && p.ff == 2 && lz[nd][i].ss >= p.ss)) lz[nd].erase(lz[nd].begin() + i);

	for (auto i : lz[nd]) {
		if (i.ff == p.ff) return;
	}

	lz[nd].push_back(p);

	if ((int)lz[nd].size() == 2) {
		if (lz[nd][0].ff == 1) lz[nd][0].ss = min(lz[nd][0].ss, lz[nd][1].ss);
		else lz[nd][0].ss = max(lz[nd][0].ss, lz[nd][1].ss);
	}
}

void LZ(int nd, int l, int r) {
	for (auto [op, h] : lz[nd]) {
		if (op == 1) st[nd] = max(st[nd], h);
		else st[nd] = min(st[nd], h);
	}

	if (l < r) {
		int ch = (nd << 1) + 1;
		for (auto i : lz[nd]) {
			Lz(ch, i); Lz(ch + 1, i);
		}
	}

	lz[nd].clear();
}

int upd(int nd, int l, int r, int x, int y, int op, int h) {
	LZ(nd, l, r);

	if (r < x || y < l) return st[nd];

	if (x <= l && r <= y) {
		Lz(nd, {op, h}); LZ(nd, l, r);
		return st[nd];
	}

	int ch = (nd << 1) + 1, md = (l + r) >> 1;
	return st[nd] = max(upd((nd << 1) + 1, l, (l + r) >> 1, x, y, op, h), upd((nd << 1) + 2, md + 1, r, x, y, op, h));
}

int fnd(int nd, int l, int r, int x) {
	LZ(nd, l, r);

	if (r < x || x < l) return 0;

	if (l == r) return st[nd];

	int ch = (nd << 1) + 1, md = (l + r) >> 1;
	return max(fnd(ch, l, md, x), fnd(ch + 1, md + 1, r, x));
}

void buildWall(int n, int k, int op[], int l[], int r[], int h[], int fh[]) {
	st.assign(n << 2, 0);
	lz.assign(n << 2, {});
	for (int i = 0; i < k; i++) upd(0, 0, n - 1, l[i], r[i], op[i], h[i]);

	for (int i = 0; i < n; i++) fh[i] = fnd(0, 0, n - 1, i);
}

컴파일 시 표준 에러 (stderr) 메시지

wall.cpp: In function 'int upd(int, int, int, int, int, int, int)':
wall.cpp:55:6: warning: unused variable 'ch' [-Wunused-variable]
   55 |  int ch = (nd << 1) + 1, md = (l + r) >> 1;
      |      ^~

• Subtask 1: 8 / 8
• Subtask 2: 24 / 24
• Subtask 3: 29 / 29
• Subtask 4: 0 / 39