Submission #1009720

#TimeUsernameProblemLanguageResultExecution timeMemory
1009720CookieMeasures (CEOI22_measures)C++14
100 / 100
299 ms26252 KiB
#include<bits/stdc++.h> #include<fstream> using namespace std; #define sz(a) (int)a.size() #define ALL(v) v.begin(), v.end() #define ALLR(v) v.rbegin(), v.rend() #define ll long long #define pb push_back #define forr(i, a, b) for(int i = a; i < b; i++) #define dorr(i, a, b) for(int i = a; i >= b; i--) #define ld double #define vt vector #include<fstream> #define fi first #define se second #define pll pair<ll, ll> #define pii pair<int, int> #define mpp make_pair const ld PI = 3.14159265359, prec = 1e-9;; //using u128 = __uint128_t; const int cox[4] = {1, 0, -1, 0}; const int coy[4] = {0, -1, 0, 1}; const ll mod = 1e9 + 7, pr = 31; const int mxn = 4e5 + 5, mxd = 250 * 250, sq = 500, mxv = 2e6 + 1; const int max_iter = 8e4, global_iter = 15e5 + 5; //const int base = (1 <<18); const ll inf = 1e16 + 5, neg = -69420, inf2 = 1e14; mt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count()); // have fun! int n, m, d; ll lz[4 * mxn + 1], mx[4 * mxn + 1], mn[4 * mxn + 1], a[mxn + 1]; int bit[mxn + 1]; ll ans = 0; void pull(int nd){ mx[nd] = max(mx[nd << 1], mx[nd << 1 | 1]); mn[nd] = min(mn[nd << 1], mn[nd << 1 | 1]); } void go(int nd, ll v){ lz[nd] += v; mx[nd] += v; mn[nd] += v; } void push(int nd){ ll &v = lz[nd]; go(nd << 1, v); go(nd << 1 | 1, v); v = 0; } void updadd(int nd, int l, int r, int ql, int qr, ll v){ if(ql > r || qr < l)return; if(ql <= l && qr >= r){ //cout << l << " " << r << " " << v << "\n"; go(nd, v); return; } int mid = (l + r) >> 1; push(nd); updadd(nd << 1, l, mid, ql, qr, v); updadd(nd << 1 | 1, mid + 1, r, ql, qr, v); pull(nd); } void updset(int nd, int l, int r, int id, ll v){ if(l == r){ //cout << l << " " << v << "\n"; mx[nd] = mn[nd] = v; return; } int mid = (l + r) >> 1; push(nd); if(id <= mid)updset(nd << 1, l, mid, id, v); else updset(nd << 1 | 1, mid + 1, r, id, v); pull(nd); //cout << l << " " << r << " " << mx[nd] << "\n"; } ll getmx(int nd, int l, int r, int ql, int qr){ if(ql > r || qr < l)return(-inf); if(ql <= l && qr >= r)return(mx[nd]); int mid = (l + r) >> 1; push(nd); return(max(getmx(nd << 1, l, mid, ql, qr), getmx(nd << 1 | 1, mid + 1, r, ql, qr))); } ll getmn(int nd, int l, int r, int ql, int qr){ if(ql > r || qr < l)return(inf); if(ql <= l && qr >= r)return(mn[nd]); int mid = (l + r) >> 1; push(nd); return(min(getmn(nd << 1, l, mid, ql, qr), getmn(nd << 1 | 1, mid + 1, r, ql, qr))); } vt<pii>comp; void upd(int p, int v){ while(p <= sz(comp)){ bit[p] += v; p += p & (-p); } } int get(int p){ int ans = 0; while(p){ ans += bit[p]; p -= p & (-p); } return(ans); } void add(pii curr){ int id = lower_bound(ALL(comp), curr) - comp.begin() + 1; ll kth = get(id - 1) + 1; updadd(1, 1, sz(comp), id + 1, sz(comp), d); upd(id, 1); updset(1, 1, sz(comp), id, kth * d - curr.fi); ans = max(ans, getmx(1, 1, sz(comp), id, sz(comp)) - getmn(1, 1, sz(comp), 1, id)); } void solve(){ cin >> n >> m >> d; for(int i = 1; i <= 4 * (n + m); i++){ mx[i] = -inf; mn[i] = inf; } for(int i = 1; i <= n + m; i++){ cin >> a[i]; comp.pb(mpp(a[i], i)); } sort(ALL(comp)); for(int i = 1; i <= n + m; i++){ add(mpp(a[i], i)); //cout << ans << ' '; if(i > n){ if(ans % 2 == 0)cout << ans / 2 << " "; else cout << fixed << setprecision(1) << ans / 2.0 << " "; } } } signed main(){ ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0); //freopen("KHONG.inp", "r", stdin); //freopen("KHONG.out", "w", stdout); int tt; tt = 1; while(tt--)solve(); return(0); }
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