제출 #1009059

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
1009059		ivopav	생물 실험 (IZhO13_expgorl)	C++17	100 / 100	2 ms	348 KiB

expgorl

#include <bits/stdc++.h>
using namespace std;

long long int dist(long long int x1,long long int y1,long long int x2,long long int y2){
  //  cout << x1 << ' ' << y1 << " " << x2 << " " << y2 << "\n";
 //   cout << abs(x1-x2) << " " <<  abs(x1-x2)*abs(x1-x2) << " " << abs(y1-y2)*abs(y1-y2) << " " << abs(y1-y2) << "\n";
    return abs(x1-x2)*abs(x1-x2)+abs(y1-y2)*abs(y1-y2);
}

int main(){
    long long int k;
    string str;
    long long int lsrx;
    long long int lsry;
    long long int grmx;
    long long int grmy;
    cin >> k >> str >> lsrx >> lsry >> grmx >> grmy;
    long long int x=0;
    long long int y=0;
    str+='I';
    long long int n=str.size();
    for (long long int i=0;i<n;i++){
        if (str[i]=='L'){
            x--;
        }
        if (str[i]=='R'){
            x++;
        }
        if (str[i]=='F'){
            y++;
        }
        if (str[i]=='B'){
            y--;
        }
    }
    long long int najm=2e9+100;
    long long int najv=0;
    for (long long int i=0;i<n;i++){
        long long int l=0;
        long long int r=k-1;
        long long int mid=k/2;
        
        while (l<r){
            long long int mid2=mid+1;
            long long int sadxmid=grmx+x*mid;
            long long int sadymid=grmy+y*mid;
            long long int sadxmid2=grmx+x*mid2;
            long long int sadymid2=grmy+y*mid2;
            long long int distmid=dist(sadxmid,sadymid,lsrx,lsry);
            long long int distmid2=dist(sadxmid2,sadymid2,lsrx,lsry);
            if (distmid<distmid2){
                r=mid;
            }
            else {
                l=mid2;
            }
            mid=(l+r)/2;
        }
        
        //cout << grmx+x*k-x << " " << grmy+y*k-y << " " << lsrx << " " << lsry << "\n";
        //cout << dist(grmx+x*k-x,grmy+y*k-y,lsrx,lsry) << "\n";
        najm=min(najm,dist(grmx+x*mid,grmy+y*mid,lsrx,lsry));
        najv=max(najv,dist(grmx,grmy,lsrx,lsry));
        najv=max(najv,dist(grmx+x*k-x,grmy+y*k-y,lsrx,lsry));
        


        if (str[i]=='L'){
            grmx--;
        }
        if (str[i]=='R'){
            grmx++;
        }
        if (str[i]=='F'){
            grmy++;
        }
        if (str[i]=='B'){
            grmy--;
        }
    }
    cout << setprecision(200) << sqrt(najm) << " " << sqrt(najv) << "\n"; 
    
}

• Subtask 1: 100 / 100