답안 #1008543

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
1008543 2024-06-26T14:14:02 Z Math4Life2020 마술쇼 (APIO24_show) C++17
0 / 100
9 ms 812 KB
// Source: https://usaco.guide/general/io

#include <bits/stdc++.h>
#include "Alice.h"
using namespace std;
using ll = long long;
using ld = long double;
using pii = pair<int,int>;
ll N = 5000;
ll E = 101;

ld seed0 = 0.1434;
ld seed = seed0;
ld getseed() {
	seed = ((ld) 3.60)*seed*(((ld) 1.0)-seed);
	return seed;
}

ll getrng(ll x) { //random integer in [0,x-1]
	return (((ll) round(10000000000*getseed()))%x);
}

ll l2(ll x) {
	return (31-__builtin_clz(x));
}

void rngreset() {
	seed=seed0;
}

vector<pii> Alice() {
	ll X = setN((int) N);
	vector<pii> vout;
	vector<bool> xv;
	for (ll e=(E-1);e>=0;e--) {
		xv.push_back((X>>e)%2);
	}
	for (ll n=1;n<N;n++) {
		ll D = l2(n)-1;
		ll val = 0;
		for (ll d=0;d<D;d++) {
			ll e = getrng(E);
			val += xv[e]*(1LL<<d);
		}
		vout.push_back({val+1,n+1});
	}
	rngreset();
	return vout;
}

long long Bob(vector<pii> V) {
	ll vals[N];
	for (ll i=0;i<N;i++) {
		vals[i]=-1;
	}
	for (pii p0: V) {
		vals[p0.second-1]=p0.first-1;
	}
	vector<ll> xv;
	ll E = 60;
	for (ll e=(E-1);e>=0;e--) {
		xv.push_back(-1);
	}
	for (ll n=1;n<N;n++) {
		ll D = l2(n)-1;
		for (ll d=0;d<D;d++) {
			ll e = getrng(E);
			//val += xv[e]*(1LL<<d);
			if (vals[n]!=-1) {
				xv[e]=(vals[n]>>d)%2;
			}
		}
	}
	ll X = 0;
	for (ll e=0;e<E;e++) {
		X += xv[e]*(1LL<<(E-1-e));
	}
	rngreset();
	return X;
}
// Source: https://usaco.guide/general/io

#include <bits/stdc++.h>
#include "Bob.h"
using namespace std;
using ll = long long;
using ld = long double;
using pii = pair<int,int>;
ll N = 5000;
ll E = 101;

ld seed0 = 0.1434;
ld seed = seed0;
ld getseed() {
	seed = ((ld) 3.60)*seed*(((ld) 1.0)-seed);
	return seed;
}

ll getrng(ll x) { //random integer in [0,x-1]
	return (((ll) round(10000000000*getseed()))%x);
}

ll l2(ll x) {
	return (31-__builtin_clz(x));
}

void rngreset() {
	seed=seed0;
}


long long Bob(vector<pii> V) {
	ll vals[N];
	for (ll i=0;i<N;i++) {
		vals[i]=-1;
	}
	for (pii p0: V) {
		vals[p0.second-1]=p0.first-1;
	}
	vector<ll> xv;
	ll E = 60;
	for (ll e=(E-1);e>=0;e--) {
		xv.push_back(-1);
	}
	for (ll n=1;n<N;n++) {
		ll D = l2(n)-1;
		for (ll d=0;d<D;d++) {
			ll e = getrng(E);
			//val += xv[e]*(1LL<<d);
			if (vals[n]!=-1) {
				xv[e]=(vals[n]>>d)%2;
			}
		}
	}
	ll X = 0;
	for (ll e=0;e<E;e++) {
		X += xv[e]*(1LL<<(E-1-e));
	}
	rngreset();
	return X;
}
# 결과 실행 시간 메모리 Grader output
1 Incorrect 9 ms 812 KB Incorrect answer.
2 Halted 0 ms 0 KB -
# 결과 실행 시간 메모리 Grader output
1 Incorrect 9 ms 812 KB Incorrect answer.
2 Halted 0 ms 0 KB -
# 결과 실행 시간 메모리 Grader output
1 Incorrect 9 ms 812 KB Incorrect answer.
2 Halted 0 ms 0 KB -