이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
#define ll long long
#define pb push_back
#define pp pop_back
#define fi first
#define se second
#define lb lower_bound
#define ub upper_bound
#define pll pair<ll,ll>
#define pii pair<int,int>
#define vl vector<ll>
#define nikah ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0);
const ll maxn = 5e5+7, modn1 = 1e9+7, modn2 = 998244353;
using namespace std;
// kalo kamu ngga emas nanti nadya merasa bersalah, ayo san demi nadya!!!
// Kalo emang soalnya susah, pindah soal dulu
// Jangan sampe diem, pikirin sesuatu, pasti bisa!!!
// Cobain semua approach, jangan ngestuck di satu pemikiran
// Jangan overthinking, jangan panik, tenangin pikiranmu
ll t,n,q;
ll a[maxn], pref[maxn];
set<pll>s;
void solve () {
cin>>n>>q;
while (q--) {
ll k; cin>>k;
for (ll i=1; i<=k; i++) {
cin>>a[i];
pref[i] = a[i] + pref[i-1];
}
ll cnt = 0;
for (ll i=k; i>=1; i--) {
ll x = min(pref[i], n);
ll y = max(n - cnt - a[i] + 1, (ll)1);
if (x >= y) {
s.insert({y,x});
}
cnt += a[i];
}
}
ll ans = 0, x = 0, y = 0, prey = 0;
for (auto p : s) {
x = p.fi; y = p.se;
if (y <= prey) continue;
if (prey == 0) {
ans += (y-x+1);
} else{
ans += (y - max(prey+1, x) + 1);
}
prey = y;
}
cout<<ans<<endl;
}
int main () {
nikah
t = 1;
// cin>>t;
while (t--) {
solve();
// cout<<endl;
}
}
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