Submission #100793

#	Time	Username	Problem	Language	Result	Execution time	Memory
100793		Bodo171	The Big Prize (IOI17_prize)	C++14	97.24 / 100	56 ms	5976 KiB

prize

#include "prize.h"
#include <fstream>
#include <vector>
#include <iostream>
#include <cmath>
using namespace std;
const int nmax=200005;
const int prdf=500;//modifici dupa asta
int lg[nmax];
int spec[nmax],norm[nmax],us[nmax];
int mx,nr,i,gasit;
vector<int> v[nmax];
int cate_st(int poz)
{
    if(v[poz].empty()) v[poz]=ask(poz);
    return v[poz][0];
}
int cate(int poz)
{
    if(v[poz].empty()) v[poz]=ask(poz);
    if(!(v[poz][0]+v[poz][1])) gasit=1;
    return (v[poz][0]+v[poz][1]);
}
int cate_dr(int poz)
{
    return (cate(poz)-cate_st(poz));
}
int n;
void solve(int st,int dr)
{
    if(st>dr) return;
    if(gasit) return;
    if(cate(st)!=cate(dr))
    {
        if(cate(st)<cate(dr))
        {
            if(!us[st])spec[++nr]=st,us[st]=1;
            solve(st+1,dr);
            return;
        }
        if(!us[dr])spec[++nr]=dr,us[dr]=1;
        solve(st,dr-1);
        return;
    }
    if(st==dr&&cate(st)<mx)
    {
        if(!us[st]) spec[++nr]=st,us[st]=1;
    }
    if(st+1>=dr) return;
    if(cate_st(st)+cate_dr(dr)==cate(st)) return;
    int m=(st+dr)/2;
    solve(st,m);
    solve(m,dr);
}
int find_best(int N) {
    n=N;
    for(i=0;i<min(prdf,n);i++)
    {
        v[i]=ask(i);
        if(v[i][0]+v[i][1]>mx)
            mx=v[i][0]+v[i][1];
    }
    spec[0]=-1;
    for(i=0;i<min(prdf,n);i++)
    {
        if(v[i][0]+v[i][1]!=mx)
            {
                ++nr;norm[i]=nr;spec[nr]=i;
                if(!cate(i)) return i;
            }

    }
    solve(prdf,n-1);
    for(i=1;i<=mx;i++)
        if(cate(spec[i])==0)
           return spec[i];
	return 0;
}

Compilation message (stderr)

prize.cpp: In function 'int find_best(int)':
prize.cpp:74:5: warning: this 'for' clause does not guard... [-Wmisleading-indentation]
     for(i=1;i<=mx;i++)
     ^~~
prize.cpp:77:2: note: ...this statement, but the latter is misleadingly indented as if it were guarded by the 'for'
  return 0;
  ^~~~~~

• Subtask 1: 20 / 20
• Subtask 2: 77.24 / 80