이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
//
// main1.cpp
// problem1
//
// Created by Mohammad Bashkail on 20/10/1445 AH.
//
#include <bits/stdc++.h>
using namespace std;
#define endl '\n'
using ll = long long;
#define pb push_back
#define pF first
#define pS second
#define SP <<" "<<
vector<bitset<21>> a;
ll a1[112345], k[112345], dp[112345], par[112345];
pair<ll,ll> m[3000];
int main() {
ios::sync_with_stdio(0);cout.tie(0); cin.tie(0);
ll n;
cin>>n;
if (n <= 5000) {
for (int i=0; i<n; i++) {
ll x;
cin>>x;
bitset<21> b(x);
a.pb(b);
}
for (int i=0; i<n; i++) cin>>k[i];
fill(dp, dp+n, 1);
fill(par, par+n, -1);
for (int i=0; i<n; i++) {
for (int j=i-1; j>=0; j--) {
bitset<21> b(a[i] & a[j]);
if (b.count() == k[i]) {
if (dp[j]+1 > dp[i]) {
par[i] = j;
dp[i] = dp[j]+1;
}
}
}
}
pair<ll,ll> mx = {-1, 0};
for (int i=0; i<n; i++) {
if (dp[i] > mx.pF) {
mx = {dp[i], i};
}
}
cout << mx.pF << endl;
ll i = mx.pS;
vector<ll> ans;
while(i != -1) {
ans.pb(i);
i = par[i];
}
reverse(ans.begin(), ans.end());
for (ll i : ans) cout << i+1 << " ";
}
else {
for (int i=0; i<n; i++) {
ll x;
cin>>x;
bitset<21> b(x);
a.pb(b);
a1[i] = x;
}
for (int i=0; i<n; i++) cin>>k[i];
for (int i=0; i<500; i++) m[i] = {-1, -1};
fill(dp, dp+n, 1);
fill(par, par+n, -1);
for (int i=0; i<n; i++) {
for (int j=0; j<500; j++) {
bitset<21> b1(j);
bitset<21> b(a[i] & b1);
if (ll(b.count()) == k[i]) {
if (m[j].pF+1 > dp[i]) {
par[i] = m[j].pS;
dp[i] = m[j].pF+1;
}
}
}
if (dp[i] > m[a1[i]].pF) {
m[a1[i]] = {dp[i], i};
}
}
pair<ll,ll> mx = {-1, 0};
for (int i=0; i<n; i++) {
if (dp[i] > mx.pF) {
mx = {dp[i], i};
}
}
cout << mx.pF << endl;
ll i = mx.pS;
vector<ll> ans;
while(i != -1) {
ans.pb(i);
i = par[i];
}
reverse(ans.begin(), ans.end());
for (ll i : ans) cout << i+1 << " ";
}
}
컴파일 시 표준 에러 (stderr) 메시지
subsequence.cpp: In function 'int main()':
subsequence.cpp:39:31: warning: comparison of integer expressions of different signedness: 'std::size_t' {aka 'long unsigned int'} and 'll' {aka 'long long int'} [-Wsign-compare]
39 | if (b.count() == k[i]) {
| ~~~~~~~~~~^~~~~~~
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