Submission #1006548

#	Time	Username	Problem	Language	Result	Execution time	Memory
1006548		andecaandeci	게임 (IOI14_game)	C++17	100 / 100	187 ms	8848 KiB

game

#include <bits/stdc++.h>
using namespace std;
// #define int long long
// #define ll long long
// #define ld long double
// #define pb push_back
// #define endl '\n'
// #define all(v) v.begin(), v.end()
// #define all1(v) v.begin() + 1, v.end()
// #define rall(v) v.rbegin(), v.rend()
// #define rall1(v) v.rbegin(), v.rend()-1
// #define fr(m,n,k) for(int m=n;m<=k;m++)
// #define frr(m,n,k) for(int m=n;m>=k;m--)
// #define yes cout << "YES"
// #define no cout << "NO"
// #define yesm cout << "Yes"
// #define nom cout << "No"
// #define inf 1e18
// #define ext {cout << -1; return;}
// #define zxt {cout << 0; return;}
// #define noxt {no;return;}
// #define yesxt {yes;return;}
// #define fill(x,s) memset(x, s, sizeof(x));
// #define lb lower_bound
// #define ub upper_bound
// #define pi pair<int,int>
// #define vi vector<int>
// #define vvi vector<vi>
// #define vs vector<string>
// #define vpi vector<pi>
// #define mii map<int,int>
// #define si set<int>
// #define fi first
// #define se second
// #define sz size()
// #define el cout<<endl

// int mod = 1e9 + 7;
// // int mod = 998244353;

// int ft(int n) {int ans = 1; for (int i = 1; i <= n; ++i) {ans = ans * i;} return ans;}
// int binpow(int x, int y) {if (y == 0) return 1; int z = 1; while (y) {  if (y & 1) z = z * x % mod; x = x * x % mod; y >>= 1;} return z;}
// int inv(int x) {return binpow(x, mod - 2);}
// int bintoint(string s) {reverse(all(s)); int xx = 0; int m = 1; int z = s.sz; fr(j, 0, z) {xx += (s[j] == '1' ? m : 0); m <<= 1;} return xx;}
// string inttobin(int x) {if (x == 0) return "0"; string s; while (x) {s += (x & 1) + '0'; x >>= 1;} reverse(all(s)); return s;}
// string ads(string s, string p) {if (s.sz > p.sz) swap(s, p); int n = s.sz, m = p.sz; reverse(all(s)); reverse(all(p)); int tm = 0; string st; fr(i, 0, n - 1) {tm = s[i] - '0' + p[i] - '0' + tm; st += '0' + tm % 10; tm /= 10;} fr(i, n, m - 1) {tm = p[i] - '0' + tm; st += '0' + tm % 10; tm /= 10;} if (tm != 0) {st += '0' + tm % 10;} reverse(all(st)); return st;}

// bool id, id1, id2;
// int n, m, k, l, r, a, b, c, d, e, x, y, z, i, j, q, t, o;
// int mi = inf, ma, sum, ans, num, cnt;
// string s, p;

// const int N = 5e5 + 5;
// mt19937 rng((int) new int);
int is[1505];
void initialize(int x) {
  
}
int hasEdge(int u, int v) {
  return (++is[max(u, v)] == max(u, v));
}
// void solve() {
// }
// signed main() {
//   ios_base::sync_with_stdio(false); cin.tie(NULL); cout.tie(0);
//   int T = 1;
//   // cin >> T;
//   for (; T--;) {
//     cout << fixed << setprecision(5); solve();
//     if (T) cout << endl;
//   } return 0;
// }
// Tc, angka kecil), No Overthink(trivial tp modified),
// Check Kasus Khusus(1,2,1e18), ganti jd bentuk lain (2 case or etc)
// bedah 1 1 variable yg bisa dicari, cari dari jwbn ke ques

// Sorting : Iterate Greedy (pake data struct) / dp / binser
// Graphs / Tree : DFS / adj / dis[a][b] != dis[a][c] + dis[c][b] / indegree
// Yang keliatan kyk dp : bisa jd brute force doang
// Data Structure : BIT / DSU / Segtree, SparseT / dequeue
// Compression, Line Sweep
// Parity (2 or 3, mod 4..) klo dilakuin 2 kali jadi sama aja -> parity mod 2

/*
brute force, greedy, pref sum, 2pointer, gcd/lcm, even/odd
min/max, binser, bfs/dfs, iterate, multiple/divisor

bipartite graph,bitmasking, sliding window, konstanta
divconquer, djikstra, stack(prev and next smaller)
prefix difference
*/

// tools :
//__lg(x),__builtinpopcount,nextpermutation(), is_sorted / alpha / digit,

• Subtask 1: 15 / 15
• Subtask 2: 27 / 27
• Subtask 3: 58 / 58