#pragma GCC optimize("Ofast")
#include<bits/stdc++.h>
#define int long long
using namespace std;
const int sz = 2e5 + 10;
int st[2][sz * 4], a[sz];
void build(int le, int ri, int v, int x) {
if (le == ri) {
if (le % 2 == x)
st[x][v] = a[le];
return;
}
int mi = le + (ri - le) / 2;
build(le, mi, v * 2, x);
build(mi + 1, ri, v * 2 + 1, x);
st[x][v] = st[x][v * 2] ^ st[x][v * 2 + 1];
}
void update(int le, int ri, int ix, int v, int k, int x) {
if (le > ix || ri < ix) return;
if (le == ix && ix == ri) {
st[x][v] = k;
return;
}
int mi = le + (ri - le) / 2;
update(le, mi, ix, v * 2, k, x);
update(mi + 1, ri, ix, v * 2 + 1, k, x);
st[x][v] = st[x][v * 2] ^ st[x][v * 2 + 1];
}
int query(int le, int ri, int ql, int qr, int v, int x) {
if (le > qr || ri < ql) return 0;
if (ql <= le && ri <= qr) return st[x][v];
int mi = le + (ri - le) / 2;
int lq = query(le, mi, ql, qr, v * 2, x);
int rq = query(mi + 1, ri, ql, qr, v * 2 + 1, x);
return lq ^ rq;
}
signed main() {
cin.tie(nullptr)->sync_with_stdio(false);
int n, q;
cin >> n >> q;
for (int i = 1; i <= n; i++) {
cin >> a[i];
}
build(1, n, 1, 0);
build(1, n, 1, 1);
while (q--) {
int t, le, ri;
cin >> t >> le >> ri;
if (1 == t) {
update(1, n, le, 1, ri, le % 2);
} else {
int d = ri - le + 1;
if (d % 2) {
cout << query(1, n, le, ri, 1, le % 2) << '\n';
} else {
cout << "0\n";
// int lq = query(1, n, le, ri - d / 2, 1, (le + 1) % 2);
// int rq = query(1, n, le + d / 2, ri, 1, (le) % 2);
// cout << (lq ^ rq) << '\n';
}
}
}
}
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Incorrect |
1 ms |
4444 KB |
Output isn't correct |
2 |
Halted |
0 ms |
0 KB |
- |
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Incorrect |
1 ms |
4444 KB |
Output isn't correct |
2 |
Halted |
0 ms |
0 KB |
- |
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Incorrect |
1 ms |
4444 KB |
Output isn't correct |
2 |
Halted |
0 ms |
0 KB |
- |